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AveGali [126]
3 years ago
8

Two painters can paint a room in 4 hours if they work together. The less experienced painter takes 3 hours more than the more ex

perienced painter to finish the job. How long does it take for the less experienced painter to paint the room individually?
Mathematics
1 answer:
Lady bird [3.3K]3 years ago
8 0
I believe it 5 hours
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100 points!!!! To whoever helps me with this!
netineya [11]

Answer:

#1: Josue's dogs

#2: see images

#3: Am group median: 25.5       Pm group median: 19

#4: Am group first Quartile = 16 Pm group first Quartile = 10

#5: Am group third Quartile = 30 Pm group third Quartile = 37

#6: see images

#7: Am group Interquartile Range = 14 Pm group Interquartile Range = 27

#8: Am group because its Interquartile gruop is smaller than the Pm group

Step-by-step explanation:

Mark as Brainliest

5 0
3 years ago
Read 2 more answers
Which pair of numbers have a greatest common factor of 7?
ella [17]
<span>The GCF is the number that is a factor of both (or all) of the numbers of a given set and which is the biggest factor of this kind (often the smaller number of the two)

7 and 14 have a greatest common factor of 7.

 28 and 7 also have a GCF of 7, so the first two responses fit.

21 and 3 have a GCF of 3, so that isn't correct.

7 and 1 have a GCF of 1, so that's incorrect as well.</span>
3 0
3 years ago
Read 2 more answers
SOMEBODY HELP PLSSSSS IT WOULD HELP ME ALOTT!!1
Oksi-84 [34.3K]
Would it be 5 ? i’m sorry i’m not very sure.
5 0
3 years ago
Read 2 more answers
What’s the answer to number 19??
Igoryamba

The answer equals 6.

Since 3 3/4 equals 15/4, when you divide you have to switch the numbers in the  divisor and then you turn the equation into multiplication.

So then it will be 15/4 x 4/3.

15 x 4 = 60

4 x 3 = 12 so the answer is 60/12. But you have to simplify so half of 60/12 is 30/6 and then half of 30/6 is 15/3 then you have to pick the gcf of 3 and 15 which is 3.

15 divided by 3 equals 5.

3 divided by 3 equals 1 so 5/1 equals 5

Hope this helps! ;)

5 0
3 years ago
Proof 1<br> Given: AB║CD , AD║CB<br> Prove: ΔABC ≅ΔCDA
lys-0071 [83]

<u>Statement                                                  Reason                                             </u>

AB║CD , AD║CB                                      Given

m∠BAC = m∠ACD                                     Alternate Interior Angles

m∠ACB = m∠CAD                                     Alternate Interior Angles

AC = AC                                                      Reflexive Property of Equality

ΔABC ≅ΔCDA                                            ASA ≅

7 0
3 years ago
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