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MrRa [10]
3 years ago
12

Help I have 10 minutes left 55 15x + 5 8 09 0.7 O 3,3

Mathematics
1 answer:
zloy xaker [14]3 years ago
8 0
Sorry for taking so long but x equals 8!

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The four corners of a square are located at (-7, -2), (-7,5), (0,5), and (0, -2). What is the perimeter of the square?
12345 [234]

Answer:

A)14 Units is the answer for this question

but check it

8 0
3 years ago
Fawzi's SUV is 6 feet 4 inches
Nat2105 [25]

Answer:

<u>9 feet 2 inches</u>

Step-by-step explanation:

Given :

⇒ Height of SUV = <u>6 feet 4 inches</u>

⇒ Height of box = <u>2 feet 10 inches</u>

<u />

============================================================

Solving :

⇒ Total Height = Height of SUV + Height of box

⇒ Total Height = 6 feet 4 inches + 2 feet 10 inches

⇒ Total Height = 8 feet 14 inches

* But, 12 inches = 1 feet *

Hence,

⇒ Total Height = 8 feet + 1 foot + 2 inches

⇒ Total Height = <u>9 feet 2 inches</u>

8 0
2 years ago
What are the roots of this equation? x2-4x+9=0
zysi [14]

Considering the definition of zeros of a function, the zeros of the quadratic function f(x) = x² + 4x +9 do not exist.

<h3>Zeros of a function</h3>

The points where a polynomial function crosses the axis of the independent term (x) represent the so-called zeros of the function.

In summary, the roots or zeros of the quadratic function are those values ​​of x for which the expression is equal to 0. Graphically, the roots correspond to the abscissa of the points where the parabola intersects the x-axis.

In a quadratic function that has the form:

f(x)= ax² + bx + c

the zeros or roots are calculated by:

x1,x2=\frac{-b+-\sqrt{b^{2}-4ac } }{2a}

<h3>This case</h3>

The quadratic function is f(x) = x² + 4x +9

Being:

  • a= 1
  • b= 4
  • c= 9

the zeros or roots are calculated as:

x1=\frac{-4+\sqrt{4^{2}-4x1x9 } }{2x1}

x1=\frac{-4+\sqrt{16-36 } }{2x1}

x1=\frac{-4+\sqrt{-20 } }{2x1}

and

x2=\frac{-4-\sqrt{4^{2}-4x1x9 } }{2x1}

x2=\frac{-4-\sqrt{16-36 } }{2x1}

x2=\frac{-4-\sqrt{-20} }{2x1}

If the content of the root is negative, the root will have no solution within the set of real numbers. Then \sqrt{-20} has no solution.

Finally, the zeros of the quadratic function f(x) = x² + 4x +9 do not exist.

Learn more about the zeros of a quadratic function:

brainly.com/question/842305

brainly.com/question/14477557

#SPJ1

6 0
1 year ago
Me papa's pp smol? I will not like papa smol pp? It will not fits me noses. How make it biggest? <img src="https://tex.z-dn.net/
Vaselesa [24]

Answer:

yeah it's small, so is yours. sorry

8 0
3 years ago
Pls help I dont understand. Find the inverse of this function.
lisov135 [29]

In the inverse we replace the place of x by y .

g(x) =  \sqrt[3]{x}  - 3 \\  \\ x =  \sqrt[3]{y}  - 3 \\  \sqrt[3]{y}  = x + 3 \\ y =  {(x + 3)}^{3}  \\ y =  {(x + 3)}^{2} (x + 3) \\ y =  ({x}^{2}  + 6x + 9)(x + 3) \\ \\  y =  {x}^{3}  + 6 {x}^{2}  + 9x + 3 {x}^{2}  + 18x + 27 \\  \\ y =  {x}^{3}  + 9 {x}^{2}  + 27x + 27 \\   \\ \\ g(x)^{ - 1}  =  {x}^{3}  + 9 {x}^{2}  + 27x + 27

I hope I helped you^_^

8 0
3 years ago
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