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2 years ago

7

5x(20 divided by 4) the power of 2 Help

2 answers:

Yanka [14]2 years ago

8 0

Do you mean 5*(20/4)^2 or (5*(20/4))^2?

because if you mean 5*(20/4)^2, then you would square the 20/4 first (so 5, which is 25 to the power of 2). then 25 times 5 is 125.

but if you mean (5*(20/4))^2, then you would multiply the 5 with (20/4), which is 25, and then square the 25, which would be 625.

valina [46]2 years ago

6 0

The answer maybe 125.

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3 years ago

A golfer keeps track of his score for playing nine holes of golf (half a normal golf round). His mean score is 8080 with a sta

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Therefore the mean and standard deviation of his total score if he plays a full 18 holes are 160 and $11\sqrt2$ respectively.

Step-by-step explanation:

Given that,

For the first 9 holes X:

E(X) = 80

SD(X)=13

For the second 9 holes Y:

E(Y) = 80

SD(Y)=13

For the sum W=X+Y, the following properties holds for means , variance and standard deviation :

E(W)=E(X)+E(Y)

and

V(W)=V(X)+V(Y)

⇒SD²(W)=SD²(X)+SD²(Y) [ Variance = (standard deviation)²]

$\Rightarrow SD(W)=\sqrt{SD^2(X)+SD^2(Y)}$

∴E(W)=E(X)+E(Y) = 80 +80=160

and

∴ $SD(W)=\sqrt{SD^2(X)+SD^2(Y)}$

$=\sqrt{11^2+11^2}$

$=\sqrt{2.11^2}$

$=11\sqrt2$

Therefore the mean and standard deviation of his total score if he plays a full 18 holes are 160 and $11\sqrt2$ respectively.

4 0

3 years ago

Apple launches an ad campaign for iPhone 12. Managers want to know what is the % of social media mentions that have positive rea

Orlov [11]

Answer:

social media mentions do managers at Apple need to collect, if they want to get a margin of error of 2%

Sample size 'n' = 625

Step-by-step explanation:

<u><em>Step(i)</em></u>:-

Given data Apple launches an ad campaign for iPhone 12

Managers want to know what is the % of social media mentions that have positive reactions to the new ad campaign

probability of positive reactions p = 1/2

Probability of negative reactions q = 1-p = 1/2

we know that $\sqrt{p(1-p}\leq \frac{1}{2}$

<u><em>Step(ii):</em></u>-

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The margin of error is determined by

$M.E = \frac{\sqrt{p(1-p} }{\sqrt{n} }$

$0.02 = \frac{\frac{1}{2} }{\sqrt{n} }$

$\sqrt{n} =\frac{1}{2 X0.02}$

√n = 25

squaring on both sides, we get

n = 625

8 0

2 years ago