All categories

3 years ago

Write your expression that uses partial products to multiply 8×64

Mathematics

1 answer:

madam [21]3 years ago

6 0

we are asked to write an expression that uses partial products to multiply 8 and 64. In this case, we can break 8 into 2 x4 and 64 into 8x8. In this case, multiplying these factors equal to 512. Any factors will do actually since it will yield the same product.

You might be interested in

Adjacent, right angles are complementary. always, sometimes, or never

IgorLugansk [536]

Adjacent right angles are Never complementary

7 0

4 years ago

Read 2 more answers

Volumes of Pyramids and Cones: Please help!

Elanso [62]

Answer:

Step-by-step explanation:256

8 0

3 years ago

The output of an economic system Q, subject to two inputs, such as labor L and capital K, is often modeled by the Cobb-Dougl

Anna35 [415]

Answer:

Step-by-step explanation:

Given

Economic system Q is given by

$Q=cL^aK^b$

also $a+b=1$

if $Q=12,200$

$a=\frac{1}{6}$

$b=\frac{5}{6}$

$c=42$

substitute these values

$12,200=42\times (L)^{\frac{1}{6}}K^{\frac{5}{6}}$

$(L)^{\frac{1}{6}}K^{\frac{5}{6}}=\frac{12,200}{42}$

$K^{\frac{5}{6}}=\frac{12,200}{42(L)^{\frac{1}{6}}}$

$K=(\frac{12,200}{42})^{\frac{6}{5}}\times \frac{1}{L^{5}}$

differentiate w.r.t to L to get $\frac{dK}{dL}$

$\frac{dK}{dL}=(\frac{12,200}{42})^{\frac{6}{5}}\times (-5)\times L^{-6}$

$\frac{dK}{dL}=-5(\frac{12,200}{42})^{\frac{6}{5}}\times \frac{1}{L^6}$

$\frac{dK}{dL}=-\frac{4515.466}{L^6}$

6 0

3 years ago

178.03 round to the nearest tens

Natali [406]

Answer:

178.0

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

PLEASEEEEEE HELPPPPPPPP

Natali5045456 [20]

The formula for the sum of n terms in an arithmetic progression is:
S = n/2 * (2a + (n-1)d)
Here, the common difference, d, is 8 and the first term, a, is 1. Substituting these into the formula, we get:

S = n/2 * (2*1 + 8(n - 1))
S = n + 4n² - 4n
S = 4n² - 3n
The answer is A.

8 0

3 years ago