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gladu [14]
3 years ago
8

Identify two additional values for x and y in a direct variation relationship where y =11 when x=18

Mathematics
1 answer:
Ann [662]3 years ago
3 0
In a direct variation relationship the values must satisfy that y = kx. This si y is always a constant value (k) times x.

So, you can find multiple values that meet this:

y = kx => k = y / x = 11 / 18

=> y = (11/18)x

Now you can give any value to x and fint the value of x that satisfy the relationship:

x           y = (11/18)x

1           11/18

2           11/18 * 2 = 11/9

18          11/18 * 18 = 11

36           11/18 * 36 = 22

So, there you have several additional values for x and y in the same relationship that y = 11 and x = 18, and you can find many more using the same rule: y = (11/18)*x
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W/3-5=3 <br> can someone help me in this question
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Hope this help!
If it's wrong sorry cause I understand the question like this
8 0
4 years ago
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Use the figure at the right to answer the following questions.
Lisa [10]

<h3><u>Answers:</u></h3>

1. Name all the line segments.

<u>Ans.</u><u> </u> PL, LA, AY, YS,

2. How many line segments were formed?

<u>Ans.</u><u> </u> 4 (four)

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<u>Ans.</u> 2 (two)

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7 0
2 years ago
A bear can run up to 18.47 feet per second. How many feet could the bear run in 3.9 seconds? 720.33 feet 7,203.3 feet 72.033 fee
JulsSmile [24]

Answer:

72.033 ft

Step-by-step explanation:

To find this, let us set up a fraction. Since 18.47 = 1 second, y = is 3.9 seconds. Let "y" be the variable.

\frac{18.47}{1}=\frac{y}{3.9}

Step 1: Switch sides

\frac{y}{3.9}=\frac{18.47}{1}

Step 2: Apply rule: \frac{a}{1}=a

\frac{y}{3.9}=18.47

Step 3: Multiply both sides by 3.9

\frac{3.9y}{3.9}=18.47\cdot \:3.9

Step 4: Simplify

y=72.033

The bear can run 72.033 feet in 3.9 seconds

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