∠A and \angle B∠B are supplementary angles. If m\angle A=(3x+18)^{\circ}∠A=(3x+18)

2 answers:

6 0

$\bf \stackrel{\textit{we know that they are supplementary}}{\stackrel{\measuredangle A}{(3x+18)}~~ + ~~\stackrel{\measuredangle B}{(5x+2)}}~~ = ~~180 \implies 8x+20=180\implies 8x=160 \\\\\\ x=\cfrac{160}{8}\implies \boxed{x = 20} ~\hfill \stackrel{\measuredangle A}{3(20)+18}\implies 78$

Alex3 years ago

5 0

Answer:

Angle A is 168 degrees and angle B is 12 degrees.

Step-by step explanation:

x=14y

14y+y=180

15y=180

y=12

x=168

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The base of a solid right pyramid is a regular hexagon with a radius of 2x units and an apothem of units. A solid right pyramid

Xelga [282]

Answer:

$6 x^2*\sqrt{3}$

Step-by-step explanation:

The base of the pyramid we need to study is a hexagon.

Let's look at the attached image of an hexagon to understand how we are going to find the area of this figure.

Notice that an hexagon is the combination of 6 exactly equal equilateral triangles in our case of size "2x" (notice that the "radius" of the hexagon is given as "2x")

Therefore the area of the hexagon is going to be 6 times the area of one of those equilateral triangles.

We know the area of a triangle is the product of its base times its height, divided by 2: $\frac{base*height}{2} = \frac{2x*height}{2}$

We notice that the triangle's height is exactly what is called the "apothem" of the hexagon (depicted in green in our figure) which measures $x\sqrt{3}$ , so replacing this value in the formula above for the area of one of the triangles: