Answer:
sin -115° = -0.91
Step-by-step explanation:
Point A is (cos 115°, sin 115°). Since cos 115° = -0.42 and sin 115° ≈ 0.91, it means that the coordinates at point A is (-0.42, 0.91).
As for point B which was revolved around -115°,
the coordinates will be similar to point A but you just have to change the negative.
B(cos -115°, sin -115°) = B(0.42, -0.91)
Answer:
A is correct
Step-by-step explanation:
The slope-intercept form:
m - slope
b - y-intercept → (0, b)
We have the point (0, 5). Therefore b = 5.
We have: y = mx + 5
Other point (3, 2). Substitute the coordinates of the point to the equation of the line:
<em>subtract 5 from both sides</em>
<em>divide both sides by 3</em>
<h3>Answer: f(x) = -1x + 5 = -x + 5</h3>
OK. These problems are easy if you know the quadratic formula,
and they're impossible if you don't.
Here's the quadratic formula:
When the equation is in the form of Ax² + Bx + C = 0
then x = [ -B plus or minus √(B²-4AC) ] / 2A
I'm sure that formula is in your text or your study notes,
right before these questions. You should cut it out or
copy it, and tape it inside the cover of your notebook.
Then, you'll always have it when you need it, until
you have it memorized and can rattle it off.
The first question says 3x² + 5x + 2 = 0
Is this in the form of Ax² + Bx + C = 0 ?
Yes ! A=3 B=5 C=2
so you can use the quadratic formula to solve it.
x = [ -B plus or minus √(B²-4AC) ] / 2A
= [ -5 plus or minus √(5² - 4·3·2) ] / 2·3
= [ -5 plus or minus √(25 - 24) ] / 6
= [ -5 plus or minus √1 ] / 6
x = -4 / 6 = -2/3
and
x = -6 / 6 = -1 .
_______________________________________
The second question says
4x² + 5x - 1 = 0
Is this in the form of Ax² + Bx + C = 0 ?
Yes it is ! A=4 B=5 C= -1
so you can use the quadratic formula to solve it.
x = [ -B plus or minus √(B²-4AC) ] / 2A
Now, you take it from here.
Answer:
7
Step-by-step explanation:
