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3 years ago

I need help please help me :(

Mathematics

1 answer:

zalisa [80]3 years ago

6 0

EXPLANATION:
10 - ( 3 + 2*2 ) + 4
=> 10 - ( 3 + 4 ) + 4
=> 10 - 7 + 4
=> 3 + 4
=> 7

ANSWER: A. 7

Hope it helps u!

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5. Cost to store: $65<br> Markup: ?<br> Selling price: $91

makvit [3.9K]

Answer:

40 %

Step-by-step explanation:

the difference between cost and selling price:

91 - 65 = 26

Find the percentage:

26/65 = 0.4 --> 40%

Markup = 40%

Hope this answer helps you :)

Have a great day

Mark brainliest

5 0

3 years ago

PLEASE HELP!!!!!!!!!!

yan [13]

$115 = l \times 2.5 \times 5.75$

$\huge \mathrm{Answer࿐}$

given :

$\longmapsto$ volume = 115 yd³

Dimensions are :

$2\frac{1}{2} yd$

$5\frac{3}{4} yd$

We know,

$\large \boxed{ \mathrm{volume = l \times b \times h}}$

$115 = 2\frac{1}{2} \times 5\frac{3}{4} \times l$

$l \times \dfrac{5}{2} \times \dfrac{23}{4} = 115$

$l \times \dfrac{115}{8} = 115$

$l = 115 \times \dfrac{8}{115}$

$l = 8 \: yd$

Therefore Length of the prism is 8 yards.

_____________________________

$\mathrm{ \#TeeNForeveR}$

5 0

3 years ago

What does the median do in a box plot

iogann1982 [59]

Answer:

the median marks the middle or the mid-point of the data and is often shown by the line that divides the box into two parts.

Step-by-step explanation:

hope this helps:)

6 0

3 years ago

Read 2 more answers

The median is 28; 16,24,x,48

Nookie1986 [14]

x = 32

To find the media, you take the middle number. If there is no discrete middle number, take the sum of the two closest to the middle and divide by 2.

(24 + x)/2 = 28

Multiply by 2 on both sides to get:

24 + x = 56

Subtract 24 from both sides to isolate the variable:

x = 56 - 24
x = 32

3 0

3 years ago

Is knowing the coordinates of the vertex of a parabola enough to determine the domain and range?

puteri [66]

The <em>correct answers</em> are:

C) No: we would need to know if the vertex is a minimum or a maximum; and

C)( 0.25, 5.875).

Explanation:

The domain of any quadratic function is all real numbers.

The range, however, would depend on whether the quadratic was open upward or downward. If the vertex is a maximum, then the quadratic opens down and the range is all values of y less than or equal to the y-coordinate of the vertex.

If the vertex is a minimum, then the quadratic opens up and the range is all values of y greater than or equal to the y-coordinate of the vertex.

There is no way to identify from the coordinates of the vertex whether it is a maximum or a minimum, so we cannot tell what the range is.

The graph of the quadratic function is shown in the attachment. Tracing it, the vertex is at approximately (0.25, 0.5875).

5 0

3 years ago

Read 2 more answers