Question

What is an equation of the line that passes through the point (6, -2) and is parallel

Answer 1

Answer:

y= -5/3x + 8

Step-by-step explanation:

parallel lines have the same slope

5x + 3y = 6

3y = -5x + 6

y = -5/3x + 2

the new line will have the slope (-5/3x)

y = (-5/3x) + b

plug in the (x, y) value to find b

-2 = -5/3(6) + b

-2 = -10 + b

b = 8

your equation is: y= -5/3x + 8