Answer:
<u>x = 60°</u>
Step-by-step explanation:
The rest of the question is the attached figure.
And it is required to find the angle x.
As shown, a rhombus inside a regular hexagon.
The regular hexagon have 6 congruent angles, and the sum of the interior angles is 720°
So, the measure of one angle of the regular hexagon = 720/6 = 120°
The rhombus have 2 obtuse angles and 2 acute angles.
one of the obtuse angles of the rhombus is the same angle of the regular hexagon.
So, the measure of each acute angle of the rhombus = 180 - 120 = 60°
So, the measure of each acute angle of the rhombus + the measure of angle x = the measure of one angle of the regular hexagon.
So,
60 + x = 120
x = 120 - 60 = 60°
<u>So, the measure of the angle x = 60°</u>
Question:
Fill in the blank.
23 x 6 = (20 + 3) * 6
23 x 6 = _ + (3x6)
Options
20 * 6
20 * 3
20 * 5
Answer:
20 * 6
Step-by-step explanation:
Given
Expression 1: 23 * 6 = (20 + 3) * 6
Expression 2: 23 * 6 = __ + (3 * 6)
Required
Fill in the blank
From Expression 1
23 * 6 = (20 + 3)*6
Using Distributive Property; The expression becomes
23 * 6 = 20 * 6 + 3 * 6
23 * 6 = (20 * 6) + (3 * 6)
By Comparing this with expression 2
23 * 6 = __ + (3 * 6)
The blank position is occupied by 20 * 6.
Hence, the correct option that fills the missing blank correctly is 20 * 6
Answer:
Step-by-step explanation:
Since the scale factor of 0.75 is less than 1, So the dilated image is a reduced image.
Thus the scale factor of 0.75 reduces the dilated image.
![\rule[225]{225}{2}](https://tex.z-dn.net/?f=%5Crule%5B225%5D%7B225%7D%7B2%7D)
Hope this helped!
<h3>~AnonymousHelper1807</h3>
Answer:
The answer is B. n+3=7
Step-by-step explanation:
^^^^^^^
Answer:
Outside the circle
Step-by-step explanation:
Let's first write the equation of this circle: 
, where (h, k) is the center and r is the radius. Here, the center is (-6, -2). We need to find the radius, which will just be the distance from N to E:
NE = 
The radius is √34, which means that r² = 34. So, our equation is:
(x + 6)² + (y + 2)² = 34
Plug in -10 for x and -7 for y:
(x + 6)² + (y + 2)² = 34
x² + 12x + 36 + y² + 4y + 4 = 34
x² + 12x + y² + 4y + 40 = 34
x² + 12x + y² + 4y + 6 = 0
(-10)² + 12 * (-10) + (-7)² + 4 * (-7) + 6 = 7
Since 7 > 0, we know that H lies outside the circle.
