What is an equation of the line that passes through the point (6, -2) and is parallel
1 answer:
Answer:
y= -5/3x + 8
Step-by-step explanation:
parallel lines have the same slope
5x + 3y = 6
3y = -5x + 6
y = -5/3x + 2
the new line will have the slope (-5/3x)
y = (-5/3x) + b
plug in the (x, y) value to find b
-2 = -5/3(6) + b
-2 = -10 + b
b = 8
your equation is: y= -5/3x + 8
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