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3 years ago

12

Can anyone solve these? Thanks.

1 answer:

lisabon 2012 [21]3 years ago

3 0

It won't let me see the picture sorry

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Select the correct responses in the table. The relationship between two numbers is described below, where x represents the first

zhenek [66]

9514 1404 393

Answer:

x² = y + 16
4y - 1 = 7x
(5, 9)

Step-by-step explanation:

Writing equations from words is mostly a matter of understanding what the English words mean.

If the first number is x, then the square of the first number is x². That is said to be equal to the sum of the second number (y) and 16:

x² = y + 16 . . . . the first equation

The wording "the difference of A and B" is usually intended to be interpreted to mean A-B. Here, we have the difference of 4 times the second number (4y) and 1, so ...

4y -1

This is equal to the first number (x) multiplied by 7, so ...

4y -1 = 7x . . . . the second equation

__

These can be solved a variety of ways. When no method is specified, I like to use a graphing calculator. It shows the only integer solution for this pair of equations is ...

(x, y) = (5, 9)

3 0

2 years ago

Find the length of side s to the nearest tenth.

stepladder [879]

Answer:

10.3

Step-by-step explanation:

So first you get the angle of T which is 25 degrees

The you use the law of sine

$\frac{s}{Sin 119} =\frac{5}{Sin 25}$

Then you get s = 10.34763268

Round to nearest tenth

s = 10.3

8 0

2 years ago

The top and bottom margins of a poster are each 15 cm and the side margins are each 10 cm. If the area of printed material on th

12345 [234]

Answer:

the dimension of the poster = 90 cm length and 60 cm width i.e 90 cm by 60 cm.

Step-by-step explanation:

From the given question.

Let p be the length of the of the printed material

Let q be the width of the of the printed material

Therefore pq = 2400 cm ²

q = $\dfrac{2400 \ cm^2}{p}$

To find the dimensions of the poster; we have:

the length of the poster to be p+30 and the width to be $\dfrac{2400 \ cm^2}{p} + 20$

The area of the printed material can now be: $A = (p+30)(\dfrac{2400 }{p} + 20)$

= $2400 +20 p +\dfrac{72000}{p}+600$

Let differentiate with respect to p; we have

$\dfrac{dA}{dp}= 20 - \dfrac{72000}{p^3}$

Also;

$\dfrac{d^2A}{dp^2}= \dfrac{144000}{p^3}$

For the smallest area $\dfrac{dA}{dp }=0$

$20 - \dfrac{72000}{p^2}=0$

$p^2 = \dfrac{72000}{20}$

p² = 3600

p =√3600

p = 60

Since p = 60 ; replace p = 60 in the expression q = $\dfrac{2400 \ cm^2}{p}$ to solve for q;

q = $\dfrac{2400 \ cm^2}{p}$

q = $\dfrac{2400 \ cm^2}{60}$

q = 40

Thus; the printed material has the length of 60 cm and the width of 40cm

the length of the poster = p+30 = 60 +30 = 90 cm

the width of the poster = $\dfrac{2400 \ cm^2}{p} + 20$ = $\dfrac{2400 \ cm^2}{60} + 20$ = 40 + 20 = 60

Hence; the dimension of the poster = 90 cm length and 60 cm width i.e 90 cm by 60 cm.

4 0

2 years ago

75 = 17 ÷2×93871788=?<br>?÷748267818=?<br>?+7376818938÷7477818199×89=?

Alchen [17]

Answer:

YOUR MOM

Step-by-step explanation:

LOLOLOLOLOLOLOLOLOLOLOLOLOLOLOLOLOLOLOLOLOLOLOLOLO)LOLOLOLOLLOllll

6 0

3 years ago

A baby girl weighed 18 lb 10 oz at 11 months and 20 lb 2 oz at 12 months. How much weight did the baby gain during this month?

SVEN [57.7K]

Answer:

B

Step-by-step explanation:

6 oz, 19lb

1 lb, 20lb

2 oz, 20lb 2oz

6oz+2oz+1lb= 1lb 8oz

4 0

2 years ago