All categories

3 years ago

Find the missing value in the ratio table. Then write the equivalent ratio

Mathematics

1 answer:

irinina [24]3 years ago

8 0

Answer:

The missing value in shirts is 28, and the missing value in jackets is 14.

Step-by-step explanation:

You might be interested in

(1 point) Find the length traced out along the parametric curve x=cos(cos(4t))x=cos⁡(cos⁡(4t)), y=sin(cos(4t))y=sin⁡(cos⁡(4t)) a

Mazyrski [523]

The length of a curve $C$ given parametrically by $(x(t),y(t))$ over some domain $t\in[a,b]$ is

$\displaystyle\int_C\mathrm ds=\int_a^b\sqrt{\left(\frac{\mathrm dx}{\mathrm dt}\right)^2+\left(\frac{\mathrm dy}{\mathrm dt}\right)^2}\,\mathrm dt$

In this case,

$x(t)=\cos(\cos4t)\implies\dfrac{\mathrm dx}{\mathrm dt}=-\sin(\cos4t)(-\sin4t)(4)=4\sin4t\sin(\cos4t)$

$y(t)=\sin(\cos4t)\implies\dfrac{\mathrm dy}{\mathrm dt}=\cos(\cos4t)(-\sin4t)(4)=-4\sin4t\cos(\cos4t)$

So we have

$\displaystyle\left(\frac{\mathrm dx}{\mathrm dt}\right)^2+\left(\frac{\mathrm dy}{\mathrm dt}\right)^2=16\sin^24t\sin^2(\cos4t)+16\sin^24t\cos^2(\cos4t)=16\sin^24t$

and the arc length is

$\displaystyle\int_0^1\sqrt{16\sin^24t}\,\mathrm dt=4\int_0^1|\sin4t|\,\mathrm dt$

We have

$\sin(4t)=0\implies4t=n\pi\implies t=\dfrac{n\pi}4$

where $n$ is any integer; this tells us $\sin(4t)\ge0$ on the interval $\left[0,\frac\pi4\right]$ and $\sin(4t)$ on $\left[\frac\pi4,1\right]$ . So the arc length is

$=\displaystyle4\left(\int_0^{\pi/4}\sin4t\,\mathrm dt-\int_{\pi/4}^1\sin4t\,\mathrm dt\right)$

$=-\cos(4t)\bigg_0^{\pi/4}-\left(-\cos(4t)\bigg_{\pi/4}^1\right)$

$=(\cos0-\cos\pi)+(\cos4-\cos\pi)=\boxed{3+\cos4}$

7 0

3 years ago

I need help with this ASAP! Its about budgeting.

Umnica [9.8K]

Answer:

Step-by-step explanation:

I gave you all of the information to fill out the first page

i also answered some of the questions on the 2nd page. They are written sideways on the page. The other questions I didn’t answer yneed calculations after you add all of the expenses together.

put the amounts from each category I listed in the image and put them into the respective category and get the total for each category. Use those totals to fill out page two. If you get stuck I don’t mind helping but I thought this is the best way to get you started.

3 0

3 years ago

Malia measured the button on her jacket. Then she calculated that it has a circumference of 25.12 millimeters. What is the butto

zmey [24]

Answer:

78.9

Step-by-step explanation:

Multiply by pi (3.14). 25.12 times 3.14 equals 78.9.

4 0

3 years ago

Let f(x) = (x − 1)2, g(x) = e−2x, and h(x) = 1 + ln(1 − 2x). (a) Find the linearizations of f, g, and h at a = 0. What do you no

sweet [91]

Answer:

Lf(x) = Lg(x) = Lh(x) = 1 - 2x

value of the functions and their derivative are the same at x = 0

Step-by-step explanation:

Given :

f(x) = (x − 1)^2,

g(x) = e^−2x ,

h(x) = 1 + ln(1 − 2x).

a) Determine Linearization of f, g and h at a = 0

L(x) = f (a) + f'(a) (x-a) ( linearization of f at a )

for f(x) = (x − 1)^2

f'(x ) = 2( x - 1 )

at x = 0

f' = -2

hence the Linearization at a = 0

Lf (x) = f(0) + f'(0) ( x - 0 )

Lf (x) = 1 -2 ( x - 0 ) = 1 - 2x

For g(x) = e^−2x

g'(x) = -2e^-2x

at x = 0

g(0) = 1

g'(0) = -2e^0 = -2

hence linearization at a = 0

Lg(x) = g ( 0 ) + g' (0) (x - 0 )

Lg(x) = 1 - 2x

For h(x) = 1 + ln(1 − 2x).

h'(x) = -2 / ( 1 - 2x )

at x = 0

h(0) = 1

h'(0) = -2

hence linearization at a = 0

Lh(x) = h(0) + h'(0) (x-0)

= 1 - 2x

Observation and reason

The Linearization is the same in every function i.e. Lf(x) = Lg(x) = Lh(x) this is because the value of the functions and their derivative are the same at x = 0

8 0

3 years ago

The area of a rectangle is represented by the formula A = lw, where I is the length

denis-greek [22]

Answer:

w= A / l

Step-by-step explanation:

A = lw

Where,

A= Area of a rectangle

l= Length of a rectangle

w= width of a rectangle

Area of a rectangle = length × width

Solve the formula(equation) for width(w).

A= lw

Divide both sides by l

A / l = lw / l

A / l = w

Width = Area of the rectangle / length of the rectangle

Example: Find the width of the rectangle with length of 6 inches and Area of 12 square inches.

A= 12 square inches

l= 6 inches

w= x inches

A= lw

w= A / l

= 12 / 6

= 2

w = 2 inches

6 0

4 years ago