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4 years ago

SOMEONE SMART 15 POINTS simplifying radical expressions (subtraction)

Mathematics

2 answers:

coldgirl [10]4 years ago

7 0

When the radical terms are the same, just focus on the numbers that are in front of them so it's really just 6 - 9 and you get -3 (third root of 2b)

Reptile [31]4 years ago

3 0

Subtract first from second and get

-3 and the same little 3, square root, and 2b. So just change the first number to -3.

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3 years ago

Let alpha and beta be conjugate complex numbers such that frac{\alpha}{\beta^2} is a real number and alpha - \beta| = 2 \sqrt{3}

miskamm [114]

Answer:

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Step-by-step explanation:

Given that alpha and beta be conjugate complex numbers

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$\alpha = x+iy\\\beta = x-iy$

since they are conjugates

$\alpha-\beta = x+iy-(x-iy)\\= 2iy= 2i\sqrt{3} \\y =\sqrt{3}$

$\frac{\alpha}{\beta^2} }\\=\frac{x+i\sqrt{3} }{(x-i\sqrt{3})^2} \\=\frac{x+i\sqrt{3}}{x^2-3-2i\sqrt{3}} \\=\frac{x+i\sqrt{3}((x^2-3+2i\sqrt{3}) }{(x^2-3-2i\sqrt{3)}(x^2-3-2i\sqrt{3})}$

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3 years ago

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mezya [45]

Answer:

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Step-by-step explanation:

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