3 years ago

You randomly select one card from a 52-card deck. find the probability of selecting a jack or a nine.

1 answer:

5 0

There are 4 Jacks and 4 nines in each deck of cards, each one a different suit, so you would have a probability of 8/52, or 2/13 simplified.

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stealth61 [152]

Answer:

1st option

Step-by-step explanation:

4 $\frac{1}{3}$ ÷ 2 $\frac{3}{5}$ ( change mixed numbers into improper fractions )

= $\frac{13}{3}$ ÷ $\frac{13}{5}$

To perform the division

leave 1st fraction, change ÷ to × , turn 2nd fraction ' upside down'

= $\frac{13}{3}$ × $\frac{5}{13}$

7 0

2 years ago

Kisachek [45]

No, the question is not a statistical question.

3 0

3 years ago

Alborosie

I will help u if u need it

7 0

3 years ago

AleksandrR [38]

Answer:

It is 150.

Step-by-step explanation:

This clarifies it https://artofproblemsolving.com/wiki/index.php/2020_AMC_8_Problems/Problem_23

5 0

2 years ago

zysi [14]

Second one if you distribute the first expression you get the second equation so the expressions are equivalent

6 0

3 years ago

You randomly select one card from a​ 52-card deck. find the probability of selecting a jack or a nine.