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arsen [322]
3 years ago
10

Apply the projectile formula to a real-world situation.

Mathematics
1 answer:
Kamila [148]3 years ago
4 0

Answer:

projectile motion

Step-by-step explanation:

If the initial velocity v0 is allowed to be zero, here is one:

You are standing next to a very deep hole, and wonder what is the depth h? You drop a stone into the hole, and hear a delayed sound (of the stone hitting the bottom) after time T on your stopwatch. Given the gravitational constant g, given the speed of sound c, and by ignoring air-resistance on the stone, calculate the depth h.

Solution:

h = cT+c2g[1−1+2gTc−−−−−−−√].

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A) 3x+2

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Evaluate<br> 2^9 over 2^5
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2^4  or 16

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Point S is on line segment RT.Given RT = 3x, RS = 3x - 5, and
Yanka [14]

Answer:

LETS TAKE AS R-S-T

d(rt)=d(rs)+d(rs)

3x=3x-5+3x-5

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Step-by-step explanation:

plz mark as brainliast

indian genius sarthak

for this effort thank the answer

6 0
3 years ago
Determine the value of x.
Akimi4 [234]

Answer:   \frac{10}{\sqrt{3}}

This is equivalent to \frac{10\sqrt{3}}{3}

======================================================

Explanation:

To get the first value mentioned above, we simply divide the long leg (10) over the square root of 3.

This is due to the fact that if x is the short leg, then x*sqrt(3) is the long leg. We go in reverse of this process to go from long leg to short leg.

The expression \frac{10}{\sqrt{3}} is the same as \frac{10\sqrt{3}}{3} after we multiply top and bottom by sqrt(3) to rationalize the denominator.

Side notes:

  • This entire process only applies to 30-60-90 triangles.
  • The hypotenuse of a 30-60-90 triangle is twice as long as the short leg, so the hypotenuse is 2x = 2*\frac{10\sqrt{3}}{3} = \frac{20\sqrt{3}}{3}  units long.
  • You could use the tangent ratio to help isolate x. You would either say tan(30) = x/10 or tan(60) = 10/x as the first equation to set up.
8 0
3 years ago
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