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tresset_1 [31]
4 years ago
13

Find the difference:

Mathematics
1 answer:
VLD [36.1K]4 years ago
6 0

Answer: The difference cannot be found because the indices of the radicals are not the same.

Step-by-step explanation:

To find the difference you need to subtract the radicals. But it is important ot remember the following: To make the subtraction of radicals, the indices and the radicand must be the same.

In this case you have these radicals:

\sqrt[ {8ab}^{3} ]{{ac}^{2} }- \sqrt[ {14ab}^{3}]{{ac}^{2} }

You can observe that the radicands are the same, but their indices are not the same.

Therefore, since the indices are different you cannot subtract these radicals.

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4x+5y=20 in point slope form
Anna35 [415]

Answer:

y = -4/5x - 4

Step-by-step explanation:

y - y1 = m(x-x1)

4x + 5y = 20 ( subtract 4x on both sides)

5y = -4x + 20 (divide by 5 on each side)

y = -4/5x + 4

So we know one point is (0,4) y-intercept

now plug in (0,4)

y - 4 = -4/5(x-0) (Distribute -4/5 to x - 0)

y - 4 = -4/5x (now add 4 on each side)

y = -4/5x - 4

4 0
3 years ago
Read 2 more answers
Which fraction is equivalent to 2/3? A. 4/9 B. 18/21 C.6/8 D. 16/24
Alexus [3.1K]

Answer:

16/24

Step-by-step explanation:

2 x 8 = 16

3 x 8 = 24

5 0
3 years ago
Shira's math test included a survey question asking how many hours students spent studying for the test. The scatter plot below
andre [41]

Answer:

10x+45

Step-by-step explanation:

8 0
3 years ago
What does the product (-5-2i)(3+7i) equal
Marina CMI [18]
This in what I got:
(-7i)(10i)
-70i
8 0
3 years ago
There is a total of 2,512 people attending the fun fair. 5/8 of sttemdees are students and 1/4 of attendees are parents. the res
kvv77 [185]

Answer:

<u>314 of the people attending the fun fair are people living in the neighborhood</u>

Step-by-step explanation:

1. Let's review the data given to us for solving the question:

Number of people attending the fun fair = 2,512

Fraction of people attending the fun fair that are students = 5/8

Fraction of people attending the fun fair that are parents = 1/4

Rest of the people attending the fun fair lives in the neighborhood

2. Let's calculate the number of students, parents and people living in the neighborhood

Students:

Fraction of people attending the fun fair that are students = 5/8

5/8 * 2,512 = 1,570

1,570 of the people attending the fun fair are students

Parents:

Fraction of people attending the fun fair that are parents = 1/4

1/4 * 2,512 = 628

628 of the people attending the fun fair are parents

People living in the neighborhood

2,512 - 1,570 - 628 = 314

<u>314 of the people attending the fun fair are people living in the neighborhood</u>

8 0
3 years ago
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