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3 years ago

If a human weighs 115 pounds on Venus, how much would that same human weigh on Mercury?

Mathematics

2 answers:

leonid [27]3 years ago

6 0

Answer:

Ever wonder what you might weigh on Mars or The Moon? Here's your chance ... The mass of a body is a measure of how much matter it contains

Step-by-step explanation:

Ket [755]3 years ago

4 0

The human that weighs 115 pounds on Venus would weigh 48 pounds on mercury.

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Solve the equation.<br> 7-4(2w + 1) = 9w-49+ w)<br> EEE.<br> W=<br> (Simplify your answer.)

tatiyna

$7 - 4(2w + 1) = 9w - 49 + w \\ 7 - 8w - 4 = 10w - 49 \\ 10w + 8w = 7 - 4 + 49 \\ 18w = 52 \\ w = \frac{52}{18} \\ w= 2.88$

I hope I helped you^_^

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3 years ago

Subtract. 29.82 − 8.001 The difference is

maks197457 [2]

Answer:

21.819 is the difference

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3 years ago

Verify the identity sin^2(x/2)=(1-cosx)/2

horsena [70]

Use the following identity:

cos(2x)=1-2sin^2(x)

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4 years ago

How do I get the answer to 60% of what number is 45

Svetradugi [14.3K]

You would do rb=p s and plug in the numbers. So your equation would look like: .60(b)=45 you would divide both sides by .60 and you would get 75. So, b=75. So your answer would be that 45 is 60% of 75

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4 years ago

Read 2 more answers

I need help with 34 it’s exponents

Romashka-Z-Leto [24]

Answer:

$\frac{x^6}{216y^9}$

Step-by-step explanation:

I'm gonna assume your assignment is to rewrite without negative exponents?

$(6x^{-2}y^3)^{-3}$

multiply the exponent into the parentheses, $(a^{b} )^c = a^{bc}$

$(6x^{-2}y^3)^{-3}$ = $6^{-3} x^6y^{-9}$

now move the negative exponents "downstairs"

$6^{-3} x^6y^{-9}$ = $\frac{x^6}{6^3*y^9}$

negative exponents in denominator move up, in numerator move down

simplifying now

$\frac{x^6}{6^3*y^9}$ = $\frac{x^6}{216y^9}$

the other way to do this is to move the entire inside down, then multiplying the exponent, like this

$(6x^{-2}y^3)^{-3}$ = $\frac{1}{(6x^{-2}y^3)^{3}} =\frac{1}{6^3*x^{-6}y^9}$

then move things up and down

both ways will get you the same answer

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3 years ago

Read 2 more answers