These problems are based on the Pythagorean Theorem. The Pythagorean Theorem is a^2 + b^2 = c^2. If the two sides are equal, the triangle is a right triangle. If c^2 is less, the triangle is acute. If c^2 is more, the triangle is obtuse.
Obtuse: c^2 > a^2 + b^2
Acute: c^2 < a^2 + b^2
Right: c^2 = a^2 + b^2
#7 --- Obtuse
21^2 ___ 8^2 + 15^2
441 ___ 64 + 225
441 > 289
#8 --- Right
20^2 ___ 12^2 + 16^2
400 ___ 144 + 256
400 = 400
#9 --- Acute
6^2 ___ 4^2 + 5^2
36 ___ 16 + 25
36 < 41
Hope this helps!
The Law of Cosines would be your best bet here, since the unknown side is opposite the known angle 110 degrees.
|AC|^2 = (8 in)^2 + (23 in)^2 - 2(8 in)(23 in)*cos 110 degrees
= 64 in^2 + 529 in^2 - (368 in^2)*(-0.342)
= 593 in^2 + 126 in ^2 approximately
= 719 in^2 approximately
Then the length of side AC is approx. √(716 in^2) = 27 in
Answer: 45
Step-by-step explanation:
By the tangent secant theorem we have AB^2 = BD(BD + CD)
So...
14^2 = 4(CD +4)
196 = 4CD + 16
4CD = 180
CD = 45
B for question five bc u have to do length times width and you’ll get the area
