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choli [55]
4 years ago
7

Y = 2x – 1; (-4, ),(0, ),(7, )

Mathematics
1 answer:
spin [16.1K]4 years ago
6 0

Answer:

Step-by-step explanation:

input all the x values into the equation

(-4,-9)

(7,13)

(0,-1)

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Hansen won the raffle At the zoo and gets to feed the dolphins! The dolphin trainer gives Hansen a bucket of fish to divide even
Pachacha [2.7K]

Answer:

Number of dolphins in zoo * number of fish per dolphin.

Step-by-step explanation:

Hansen won the raffle At the zoo and gets to feed the dolphins! The dolphin trainer gives Hansen a bucket of fish to divide evenly among five dolphins. Each dolphin gets four fish. Which equation can you use to find the number of fish F in the bucket before hansen feeds them

Given that:

Number of dolphins = 5

Fish in bucket is distributed equally ; hence, Number of fish per dolphin = 4

To obtain the initial number of fish in bucket before hansen began to feed the fishes :

Number of fish in bucket before hansen feeds then :

Number of dolphins in zoo * number of fish per dolphin.

5 * 4 = 20

6 0
3 years ago
What percent of 96.4 is 23.4
Kipish [7]

Answer:

x = 24.27385%

Step-by-step explanation:

We can say 96.4x=23.4

Divide by 96.4: (x=23.4/96.4) = 0.24273858921

x=0.24273858921 so x = 24.27385...%

7 0
2 years ago
Please help! Identify the recursive formula for the sequence 20, 28, 36, 44, . . . .
r-ruslan [8.4K]

Option A

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8 0
3 years ago
Use Euler's method with step size 0.2 to estimate y(1), where y(x) is the solution of the initial-value problem y' = x2y − 1 2 y
irina [24]

Answer:

Therefore the value of y(1)= 0.9152.

Step-by-step explanation:

According to the Euler's method

y(x+h)≈ y(x) + hy'(x) ....(1)

Given that y(0) =3 and step size (h) = 0.2.

y'(x)= x^2y(x)-\frac12y^2(x)

Putting the value of y'(x) in equation (1)

y(x+h)\approx y(x) +h(x^2y(x)-\frac12y^2(x))

Substituting x =0 and h= 0.2

y(0+0.2)\approx y(0)+0.2[0\times y(0)-\frac12 (y(0))^2]

\Rightarrow y(0.2)\approx 3+0.2[-\frac12 \times3]    [∵ y(0) =3 ]

\Rightarrow y(0.2)\approx 2.7

Substituting x =0.2 and h= 0.2

y(0.2+0.2)\approx y(0.2)+0.2[(0.2)^2\times y(0.2)-\frac12 (y(0.2))^2]

\Rightarrow y(0.4)\approx  2.7+0.2[(0.2)^2\times 2.7- \frac12(2.7)^2]

\Rightarrow y(0.4)\approx 1.9926

Substituting x =0.4 and h= 0.2

y(0.4+0.2)\approx y(0.4)+0.2[(0.4)^2\times y(0.4)-\frac12 (y(0.4))^2]

\Rightarrow y(0.6)\approx  1.9926+0.2[(0.4)^2\times 1.9926- \frac12(1.9926)^2]

\Rightarrow y(0.6)\approx 1.6593

Substituting x =0.6 and h= 0.2

y(0.6+0.2)\approx y(0.6)+0.2[(0.6)^2\times y(0.6)-\frac12 (y(0.6))^2]

\Rightarrow y(0.8)\approx  1.6593+0.2[(0.6)^2\times 1.6593- \frac12(1.6593)^2]

\Rightarrow y(0.6)\approx 0.8800

Substituting x =0.8 and h= 0.2

y(0.8+0.2)\approx y(0.8)+0.2[(0.8)^2\times y(0.8)-\frac12 (y(0.8))^2]

\Rightarrow y(1.0)\approx  0.8800+0.2[(0.8)^2\times 0.8800- \frac12(0.8800)^2]

\Rightarrow y(1.0)\approx 0.9152

Therefore the value of y(1)= 0.9152.

4 0
3 years ago
a person with typical deductions earning $75,000 per year would have saved 2% of their income plus $850 in federal taxes. How mu
AURORKA [14]
Am pretty sure you should add 2 to both of the numbers than multiple I THINK.
7 0
3 years ago
Read 2 more answers
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