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djverab [1.8K]
3 years ago
12

Simplify 6n^2 - 5n^2 + 7n^2

Mathematics
1 answer:
dusya [7]3 years ago
3 0
Take out the variable to add the numbers because it is the same variable throughout so 6-5+7=8 then add the n^2 o get 8n^2
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Can someone help me out how to work on this.
enyata [817]

Answer:

I don't think any are a correct graph of the function. But here are the ordered pairs. (1,0),(0,-2),(-1,-4)

Step-by-step explanation:

Take three values for x and plug them in for your y's. For instance x values of 1,0,-1. Plug each in to find the y value. 2(1) - 2 =y so (1,0)

3 0
4 years ago
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Match each of the trigonometric expressions below with the equivalent non-trigonometric function from the following list. Enter
Levart [38]

Answer:

Match each of the trigonometric expressions below with theequivalent non-trigonometric function from the following list.Enter the appropiate letter(A,B, C, D or E)in each blank

A . tan(arcsin(x/8))

B . cos (arsin (x/8))

C. (1/2)sin (2arcsin (x/8))

D . sin ( arctan (x/8))

E. cos (arctan (x/8))

These are the spaces to fill out :

.. ..........x/64 (sqrt(64-x^2))

.............x/sqrt(64+x^2)

.............sqrt(64-x^2)/8

..............x/sqrt(64-x^2)

..............8/sqrt(64+x^2)

A. ........tan(arcsin(x/8))  =......x/sqrt(64-x^2)

B .      cos (arsin (x/8))  ....sqrt(64-x^2)/8

Step-by-step explanation:

To solve this we have to find the missing sides to each of the triange discribed in prenthesis thus

A we have the sides of the triangle given by x, 8 and  \sqrt{8^{2} - x^{2} }or  \sqrt{64 - x^{2} }

thus tan(arcsin(x/8))  = \frac{x}{\sqrt{64 - x^{2} }}  =

Therefore  ........tan(arcsin(x/8))  =......x/sqrt(64-x^2)

B

Here we have cos = adjacent/hypotenuse where adjacent side is \sqrt{64 - x^{2} } and hypothenuse = 8 we have \sqrt{64 - x^{2} }/8

B .      cos (arsin (x/8))  ....sqrt(64-x^2)/8

4 0
3 years ago
PLEASE HELP WILL GIVE BRAINLIEST TO CORRECT ANSWER
dem82 [27]

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8 0
3 years ago
Read 2 more answers
4(1 - 4r) + 5(r - 7)
Makovka662 [10]

Answer:4\left(1-4r\right)+5\left(r-7\right)=-11r-31

Step-by-step explanation:

5 0
4 years ago
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use the domain {-4, -2, 0, 2, 4} the codomain [-4, -2, 0, 2, 4} and the range {0, 2, 4} to create a function that is niether one
lesya [120]

Answer:

See attachment

Step-by-step explanation:

We want to create a function that is neither one-to-one or on to given that:

The domain is {-4, -2, 0, 2, 4}

The codomain is [-4, -2, 0, 2, 4}

The range is  {0, 2, 4}

The function in the attachment is an example of such function.

The function is not one-to-one because there are different different x-value in the domain that has the same y-value in the co-domain.

It is not an on to function because the range is not equal to the co-domain.

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