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3 years ago

15

a rope is 24 feet long. it is cut into two pieces such that one piece is half the length of the other. find the lengths of the t

wo pieces of rope

2 answers:

marishachu [46]3 years ago

4 0

Answer:

THE STATED SOLUTION IS CORRECT (LENGTHS OF 16 FEET AND 8 FEET)

BASED ON THE WAY THE VARIABLE IF DEFINED THE EQUATION SHOULD BE X+2 X=24 .

THE WAY THE VARIABLE IS DEFINED AND BECAUSE X=16 THE LONGER PIECE OF ROPE WOULD BE 32 FEET, WHICH IS NOT POSSIBLE . SO A, B, AND D ARE YOUR ANSWERS ON E20 (JUST FINISHED THE QUESTION )

Step-by-step explanation:

Ivahew [28]3 years ago

3 0

Answer:

16 ft and 8 ft

Step-by-step explanation:

x + 1/2 x=24

2/2 x + 1/2 x= 24

3/2 x=24

3 x= 48

x=16

1/2x=16/2=8

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Is 10-2x is less then 10 what is x

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3 years ago

Find the work done by F= (x^2+y)i + (y^2+x)j +(ze^z)k over the following path from (4,0,0) to (4,0,4)

babunello [35]

$\vec F(x,y,z)=(x^2+y)\,\vec\imath+(y^2+x)\,\vec\jmath+ze^z\,\vec k$

We want to find $f(x,y,z)$ such that $\nabla f=\vec F$ . This means

$\dfrac{\partial f}{\partial x}=x^2+y$

$\dfrac{\partial f}{\partial y}=y^2+x$

$\dfrac{\partial f}{\partial z}=ze^z$

Integrating both sides of the latter equation with respect to $z$ tells us

$f(x,y,z)=e^z(z-1)+g(x,y)$

and differentiating with respect to $x$ gives

$x^2+y=\dfrac{\partial g}{\partial x}$

Integrating both sides with respect to $x$ gives

$g(x,y)=\dfrac{x^3}3+xy+h(y)$

Then

$f(x,y,z)=e^z(z-1)+\dfrac{x^3}3+xy+h(y)$

and differentiating both sides with respect to $y$ gives

$y^2+x=x+\dfrac{\mathrm dh}{\mathrm dy}\implies\dfrac{\mathrm dh}{\mathrm dy}=y^2\implies h(y)=\dfrac{y^3}3+C$

So the scalar potential function is

$\boxed{f(x,y,z)=e^z(z-1)+\dfrac{x^3}3+xy+\dfrac{y^3}3+C}$

By the fundamental theorem of calculus, the work done by $\vec F$ along any path depends only on the endpoints of that path. In particular, the work done over the line segment (call it $L$ ) in part (a) is

$\displaystyle\int_L\vec F\cdot\mathrm d\vec r=f(4,0,4)-f(4,0,0)=\boxed{1+3e^4}$

and $\vec F$ does the same amount of work over both of the other paths.

In part (b), I don't know what is meant by "df/dt for F"...

In part (c), you're asked to find the work over the 2 parts (call them $L_1$ and $L_2$ ) of the given path. Using the fundamental theorem makes this trivial:

$\displaystyle\int_{L_1}\vec F\cdot\mathrm d\vec r=f(0,0,0)-f(4,0,0)=-\frac{64}3$

$\displaystyle\int_{L_2}\vec F\cdot\mathrm d\vec r=f(4,0,4)-f(0,0,0)=\frac{67}3+3e^4$

8 0

3 years ago

please help me, i only get 2 chances to answer, and this is my last change, and i need help with math so bad

likoan [24]

67 percent
Which is 99000 x .67

6 0

3 years ago

Choices:<br><br> One-sixth cups<br> Five-sixths cups<br> 1 and two-thirds cups<br> 1 and 5 / 6 cups

navik [9.2K]

Answer:

Patel will require more orange juice = $\frac{371}{660}$ cups

Step-by-step explanation:

Patel needs the orange juice for his family = 3 cups

He needs more orange juice = 3 cups - Sum of juice squeezed from different oranges

$=3-(\frac{13}{15}+\frac{1}{5}+\frac{9}{20}+\frac{5}{11}+\frac{7}{15})$

L.C.M. of the denominators = 660

$=3-\frac{572+132+297+300+308}{660}$

$=3-\frac{1609}{660}$

= $\frac{1980-1609}{660}$

= $\frac{371}{660}$

Therefore, amount of orange juice required more = $\frac{371}{660}$ cups

3 0

3 years ago