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Rudik [331]
3 years ago
15

a rope is 24 feet long. it is cut into two pieces such that one piece is half the length of the other. find the lengths of the t

wo pieces of rope
Mathematics
2 answers:
marishachu [46]3 years ago
4 0

Answer:

THE STATED SOLUTION IS CORRECT (LENGTHS OF 16 FEET AND 8 FEET)

BASED ON THE WAY THE VARIABLE IF DEFINED THE EQUATION SHOULD BE X+2 X=24 .

THE WAY THE VARIABLE IS DEFINED AND BECAUSE X=16 THE LONGER PIECE OF ROPE WOULD BE 32 FEET, WHICH IS NOT POSSIBLE .  SO A, B, AND D ARE YOUR ANSWERS ON E20 (JUST FINISHED THE QUESTION )

Step-by-step explanation:

Ivahew [28]3 years ago
3 0

Answer:

16 ft and 8 ft

Step-by-step explanation:

x + 1/2 x=24

2/2 x + 1/2 x= 24

3/2 x=24

3 x= 48

x=16

1/2x=16/2=8

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For the function y = 3x, if the input (x) is -2, what is the output (y) ?
Dmitry [639]

Answer:

-6

Step-by-step explanation:

2*-3=-6

rule of thumb: a double negative equals a positive in multiplication or division

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2 years ago
Which is an x-intercept of the continuous function in the table?
azamat

Answer:

(-6,0)

(3,0)

Step-by-step explanation:

3 0
3 years ago
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If AB = 21 centimeters, and BC = 28 centimeters, which does AC equal?
Bad White [126]

yup the answer would be c have a nice day :)

7 0
3 years ago
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Aquarius is an underwater ocean laboratory located in the Florida keys national marine sanctuary. Solve the equation 31/25x = -6
serg [7]

Answer:

x=-50

Step-by-step explanation:

31/25x=-62

x=-62/(31/25)

x=(-62/1)(25/31)

x=--1550/31

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4 0
3 years ago
Ayuda por favor
sergeinik [125]

A partir de la definición de razón y la teoría de semejanza entre triángulos, la razón del área del triángulo AMN y el área del cuadrilátero BMNC es equivalente a 1/3.

<h3>¿Cómo determinar la medida de un lado de un triángulo desconocido?</h3>

En este problema tenemos un sistema formado por dos triángulos <em>similares</em>, la semejanza entre los dos triángulos se debe a la colinealidad entre los segmentos de línea AP' (triángulo <em>pequeño</em>) y AP'' (triángulo <em>grande</em>), así como de los lados AM y AB, así como los lados AN y AC, así como los <em>mismos</em> ángulos en la <em>misma</em> distribución. (Semejanza Lado - Ángulo - Lado)

En consecuencia, obtenemos las siguientes proporciones:

AP'/AP'' = MN/BC = 1/2     (1)

Finalmente, la proporción entre el triángulo AMN y el cuadrilátero BMNC es:

\frac{AMN}{ABC - AMN} = \frac{\frac{1}{2}\cdot a \cdot \left(\frac{1}{2}\cdot h \right)}{\frac{1}{2}\cdot (2\cdot a) \cdot  h - \frac{1}{2}\cdot a \cdot \left(\frac{1}{2}\cdot h \right)} = \frac{\frac{1}{4}\cdot a\cdot h }{a\cdot h - \frac{1}{4}\cdot a \cdot h }

\frac{AMN}{ABC - AMN} = \frac{\frac{1}{4} }{\frac{3}{4} } = \frac{1}{3}

A partir de la definición de razón y la teoría de semejanza entre triángulos, la razón del área del triángulo AMN y el área del cuadrilátero BMNC es equivalente a 1/3.

Para aprender sobre triángulos semejantes: brainly.com/question/21730013

#SPJ1

3 0
2 years ago
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