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3 years ago

What is the difference between constructing and drawing geometric figures? Give a real-world example of each.

Mathematics

2 answers:

wolverine [178]3 years ago

8 0

The difference between constructing and drawing geometric figures is as follows:

To construct geometric figure you use many tools like protractor, compass, ruler, scale, square, among others. So you need an accurate representation of the geometric figure. On the other hand, to draw a geometric figure you only need a pencil to do that. You don't need an accurate representation of the geometric figure.

A real-world example of each:

Think about an civil engineer who is constructing a building. He would need many tools to do that. In fact, he would need an building which is an accurate representation of the drawings he made using a software. He would need the accurate measurements and the correct location of each characteristic points of the building. So, this is the construction. On the other hand, when starting with the project, the civil engineer maybe took a paper and began drawing an sketch of his building, he only needed a pencil to do that, so this is the drawing made by hand.

NikAS [45]3 years ago

7 0

The difference between constructing and drawing geometric figures is that when constructing a geometric figure, you use compass, protractor, ruler, or any scale with accurate measurement while when drawing geometric figures, you just draw with free-hand. It is not exact in measures.

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Ket [755]

Answer:

approx 58 yard we can determine it by pithagoras theorem

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3 years ago

Solve the problem. Use the Central Limit Theorem.The annual precipitation amounts in a certain mountain range are normally distr

bazaltina [42]

Answer:

0.8944 = 89.44% probability that the mean annual precipitation during 25 randomly picked years will be less than 112 inches.

Step-by-step explanation:

To solve this question, we use the normal probability distribution and the central limit theorem.

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the z-score of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem establishes that, for a normally distributed random variable X, with mean $\mu$ and standard deviation $\sigma$ , the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean $\mu$ and standard deviation $s = \frac{\sigma}{\sqrt{n}}$ .

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

Mean of 109.0 inches, and a standard deviation of 12 inches.

This means that $\mu = 109, \sigma = 12$

Sample of 25.

This means that $n = 25, s = \frac{12}{\sqrt{25}} = 2.4$

What is the probability that the mean annual precipitation during 25 randomly picked years will be less than 112 inches?

This is the p-value of Z when X = 112. So

$Z = \frac{X - \mu}{\sigma}$

By the Central Limit Theorem

$Z = \frac{X - \mu}{s}$

$Z = \frac{112 - 109}{2.4}$

$Z = 1.25$

$Z = 1.25$ has a p-value of 0.8944.

0.8944 = 89.44% probability that the mean annual precipitation during 25 randomly picked years will be less than 112 inches.

7 0

3 years ago

I need help on all of #1

grandymaker [24]

I think it's fractions

6 0

2 years ago

Use the commutative and associative properties as needed to simplify the expression. (12+a)+14

timama [110]

Answer:

26+a

Step-by-step explanation:

(12+a)+14

(12+14)+a

26+a

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3 years ago

You have 6 reindeer, Prancer, Rudy, Balthazar, Quentin, Jebediah, and Lancer, and you want to have 3 fly your sleigh. You always

velikii [3]

Answer:

120 ways.

Step-by-step explanation:

We have been given that you have 6 reindeer, Prancer, Rudy, Balthazar, Quentin, Jebediah, and Lancer, and you want to have 3 fly your sleigh. You always have your reindeer fly in a single-file line.

We will use permutation formula to solve our given problem as:

$_{r}^{n}\textrm{C}=\frac{n!}{(n-r)!}$