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worty [1.4K]
3 years ago
7

What is the difference between constructing and drawing geometric figures? Give a real-world example of each.

Mathematics
2 answers:
wolverine [178]3 years ago
8 0

<em><u>The difference between constructing and drawing geometric figures is as follows:</u></em>


To construct geometric figure you use many tools like protractor, compass, ruler, scale, square, among others. So you need an accurate representation of the geometric figure. On the other hand, to draw a geometric figure you only need a pencil to do that. You don't need an accurate representation of the geometric figure.


<u><em>A real-world example of each:</em></u>


Think about an civil engineer who is constructing a building. He would need many tools to do that. In fact, he would need an building which is an accurate representation of the drawings he made using a software. He would need the accurate measurements and the correct location of each characteristic points of the building. So, this is the construction. On the other hand, when starting with the project, the civil engineer maybe took a paper and began drawing an sketch of his building, he only needed a pencil to do that, so this is the drawing made by hand.

NikAS [45]3 years ago
7 0
The difference between constructing and drawing geometric figures is that when constructing a geometric figure, you use compass, protractor, ruler, or any scale with accurate measurement while when drawing geometric figures, you just draw with free-hand. It is not exact in measures. 
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Answer:

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Step-by-step explanation:

a. The volume of water initially in the fish tank = 15 liters

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The rate at which the mixture is drained = 5 liters per minute

The amount of salt in the fish tank after t minutes = x

Where the volume of water with x grams of salt = 15 liters

dx =  (5·c - 5·c/3)×dt = 20/3·c = 6\frac{2}{3} \cdot c \cdot dt

\dfrac{dx}{dt} = 6\frac{2}{3} \cdot c

b. The amount of salt, x after t minutes is given by the relation

\dfrac{dx}{dt} = 6\frac{2}{3} \cdot c

dx = 6\frac{2}{3} \cdot c \cdot dt

x(t) = \int\limits \, dx  = \int\limits \left ( 6\frac{2}{3} \cdot c \right) \cdot dt

x(t) = 6\frac{2}{3} \cdot c \cdot t

c. Given that in 10 minutes, the amount of salt in the tank = 25 grams, and the volume is 15 liters, we have;

x(10) = 25 \ grams(15 \ in \ liters) = 6\frac{2}{3} \times c \times 10

6\frac{2}{3} \times c  =\dfrac{25 \ grams }{10}

c  =\dfrac{25 \ g/L }{10 \times 6\frac{2}{3} }  = \dfrac{25 \ g/L}{10 \times \dfrac{20}{3} } =\dfrac{3}{200} \times 25 \ g/L= \dfrac{75}{200}  \ g/L = \dfrac{3}{8}  \ g/L

c  = \dfrac{3}{8}  \ g/L

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Answer:

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Answer:

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