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Arlecino [84]
3 years ago
9

Please help need answer

Mathematics
2 answers:
Crank3 years ago
8 0
The answer is c i think
rusak2 [61]3 years ago
7 0
C. A and B are nothing
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Number 21 please and thank you
olga2289 [7]

Answer:

\frac{5}{6}

Step-by-step explanation:

sin =opposite/hypotenuse

sinQ=5/6

7 0
2 years ago
Rectangle with a side length of 11" and a diagonal of 14" what is the perimeter
notka56 [123]

Answer:

10sqrt3+22

Step-by-step explanation:

Ok, let us imagine it as a sort of rectangle split upon its diagonal.

Using that, we can Pythag it out,

11^2+b^2=14^2

121+b^2=196

b^2=75

b=sqrt75

b=5sqrt3

Ok, using this info, we find the perimeter,

5sqrt3+5sqrt3+11+11

10sqrt3+22

The answer is 10sqrt3+22

7 0
3 years ago
Read 2 more answers
Help me answer for 11 points
Tcecarenko [31]

Answer:

Just Transposition...

Step-by-step explanation:

12×7=84=d

92-49=43=e

28+57=85=f

96÷16=6=g

11×8=88=h

95+5-29=100-29=71=I

55-6+21=70=j

88+8÷4=96÷4=16=k

19+24-97=-97-43=54=m

-20+17+61=61+3=64=n

hope it helps

4 0
3 years ago
Mai biked 6\frac{3}{4} miles today, and Noah biked 4\frac{1}{2} miles.
Alinara [238K]

It was 1.5 times the length of Noah's bike ride as Mai’s bike ride.

The problem we dealing with is related to mixed numbers which are referred to as mixed numbers and could be the whole number, and a proper division spoke together. It for the most part speaks to a number between any two whole numbers.

Since we are providing mai's rate which is  6 3/4  miles and Noah's  rate of 4 1/2 miles, So in  order to find the time the length of Noah's ride is compared to Mal's, we just need to divide the given rates by each other

=> 6 3/4 divided by 4 1/2,  

=> 27/4 divided by 9/2, (The result is an improper fractions)

=> 27/4 X 2/9

=>3/2

=> 1.5

To know more about mixed numbers refer to the link  brainly.com/question/24137171?referrer=searchResults.

#SPJ1

3 0
10 months ago
The box plots show the weights, in pounds, of the dogs in two different animal shelters.
zimovet [89]

*see attachment below for the box plots that is being referred to

Answer:

*The median weight for shelter A is greater than that for shelter B

*The data for shelter B are a symmetric data set

Step-by-step explanation:

Let's take each stated option and examine the box plot to see which is TRUE or NOT.

OPTION 1: "The median weight for shelter A is greater than that for shelter B."

The median for shelter A = 21,

Median for shelter B = 18

Median weight for shelter A (21) is greater than that for shelter B.

This statement in this option is TRUE.

OPTION 2: "The median weight for shelter B is greater than that for shelter A."

Median for B (18) < median of A (21)

This statement in option is NOT TRUE.

OPTION 3: "The data for shelter A are a symmetric data set."

This is NOT TRUE because the length of both whiskers are unequal and also, the box is not divided equally. One side is longer than the other.

OPTION 4: "The data for shelter B are a symmetric data set."

This is TRUE because the length of both whiskers are relatively equal, and also, the rectangular box is divided equally.

OPTION 5: "The interquartile range for shelter A is 8"

This is NOT TRUE.

IQR = Q3-Q1

IQR for shelter A is approximately  = 28-17 = 11

5 0
3 years ago
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