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Dmitrij [34]
3 years ago
7

Describing each step.

Mathematics
2 answers:
Elena L [17]3 years ago
7 0
I honestly don’t have a single clue
Lena [83]3 years ago
4 0

Answer:

1) Translation

2) Rotation

3) Translation

Step-by-step explanation:

1) It is translation because you are moving the shape around but keeping it's properties the same.

2) It is rotation because you are rotaitng it around

3) Traslation same reason as 1)

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Find the measure of x.<br> X<br> 55°<br> 80<br> X<br> = [ ?<br> ]<br> Round to the nearest tenth.
NARA [144]
<h3>Answer:  139.5</h3>

Work Shown:

cos(angle) = adjacent/hypotenuse

cos(55) = 80/x

x*cos(55) = 80

x = 80/cos(55)

x = 139.4757 approximately

x = 139.5

3 0
2 years ago
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1 minus 1/2 minus 1/3 minus 1/4
serg [7]

1 - 1/2 - 1/3 - 1/4 =


     12 - 6 - 4 -3 =

_______________

            12

= -1/12  (-0.08333...)

8 0
3 years ago
What is the measure of
kondaur [170]
Edit your question so we know what you are asking
8 0
2 years ago
Find the soultion(s) to the system of equations. Select all that apply
neonofarm [45]

Answer:

(0,-3)

(3,0)

Step-by-step explanation:

The solutions to the system of equations are where the two graphs cross

The first is at x=0 and y=-3

The second is at x=3 and y=0

3 0
3 years ago
A piece of cardboard is 13 inches by 26 inches. A square is to be cut from each corner and the sides folded up to make an open-t
Vanyuwa [196]

Answer:

Hence the maximum possible volume will be the 778.53 c.c

Step-by-step explanation:

Given:

A rectangle with 13 x 26 dimensions

And corners are cut to form side squares.

To Find:

Maximum possible volume for box

Solution :

Consider a rectangle of 13 x 26 dimension with and side of square  at corner be x.

(Refer the attachment)

Now,

Formulating the volume equation for the box

So corner square sides we are going to fold up which makes height of the box

and remaining part will be length and breadth

As shown in fig,

Length=26-x

breadth=13-x

And height will be x

V(x)=x*(26-x)*(13-x)

To get maximum volume differentiate the above equation,

V(x)=x*(26*13-26*x-13*x+x^2)

V(x)=x^3-39x^2+338x\\

V'(x)=3x^2-78x+338

V''(x)=6x-78

Now ,Solve the Quadratic Equation to get x values,

3x^2-78x+338=0

x=[-b±(b^2-4ac)^1/2]/2a

x=[78±Sqrt[(78)^2-4*338*3)]/2*3

x=[78±Sqrt(3028)]/6

x=[78±55.027]/6

x=78+55.027/6 or x=78-55.027/6

x=22.17  or x=3.8288

Use these values in 6x-78 to know which value posses the max and min value for the function.

So when x=22.17

6x-78=6*22.17-78

=55.02>0  i.e function will have minimum value .

When x=3.8288

6*3.8288-78

=-55.0272<0 i.e. Function will have maximum value

Now, the function will defines the maximum volume

V(x)=x^3-39x^2+338x

V(x)=3.8288^3-39*(3.82883)^2+338*3.8288

V(x)=56.13-571.73+1294.13

V(x)=778.53 C.C

6 0
3 years ago
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