Solving a value mixture problem using a system of linear equations
1 answer:
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Answer:
see explanation
Step-by-step explanation:
The 4 sides of a rhombus are congruent.
(i)
2y + x - 4 = 2x - y ( subtract 2x - y from both sides )
3y - x - 4 = 0 ( add 4 to both sides )
3y - x = 4 → (1)
and
= 2x - y ( multiply both sides by 2 to clear the fraction )
4x - 3y + 5 = 4x - 2y ( subtract 4x - 2y from both sides )
- y + 5 = 0 ( subtract 5 from both sides )
- y = - 5 ( multiply both sides by - 1 )
y = 5
substitute y = 5 into (1)
3(5) - x = 4
15 - x = 4 ( subtract 15 from both sides )
- x = - 11 ( multiply both sides by - 1 )
x = 11
(ii)
then
2x - y = 2(11) - 5 = 22 - 5 = 17
perimeter = 4 × 17 = 68 cm
Pythagorean Theorem!
+
=
72.25+72.25=
144.5=
12.02 or just 12
72.25+72.25=
144.5=
12.02 or just 12