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svet-max [94.6K]
3 years ago
15

I need help with this​

Mathematics
1 answer:
Oksi-84 [34.3K]3 years ago
7 0
It is option 3 trust
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Write the expression in algebraic form. [hint: sketch a right triangle.] tan(arcsec(x/3))
WARRIOR [948]

Sketch  a right triangle having adjacent side(A) is given as “3”, hypotenuse side (H) is “x” and assigning angle “a” as the angle between A and H. Using Pythagorean theorem, you will get “square root of x-squared minus 9” as the opposite side (O). Using SOH CAH TOA function, and since secant is the reciprocal of cosine, sec(a) = x/3. Thus, a = arcsec(x/3). The remaining expression tan(a) is Opposite side over Adjacent side which is equal to “square root of x^2 - 9” over "3". Therefore, the algebraic expression would be: tan(arcsec(x/3)) = “sqrt (x^2 -9)” /3. Different answers can be made depending on which side you consider the “3” and “x”.

6 0
3 years ago
Shele bought a box of eggs. She wrote this equation to show the number of eggs in one box. e = 6 If Shele bought 4 boxes of eggs
dangina [55]
The equation e = 6 tells you for each box, e, there are 6 eggs. If she bought 4 boxes, you would be multiplying the number of boxes, 4, by e. That means:
4 x e 

Now you need to set 4 x e equal to the total number of eggs she has now. Since you know e = 6 eggs, plug in 6 into 4 x e!
4 x e = ?
4 x 6 = 24

That means you complete equation is:
4 x e = 24

-----

Answer: <span>A) 4 × e = 24</span>
5 0
3 years ago
The speeders soccer team charged $12 to wash each car at a fundraiser car wash.The team collected a total os $672 by the end of
sukhopar [10]

They washed 56 cars because 672/12=56

4 0
3 years ago
Read 2 more answers
What are the approximate values of the non-integral roots of the polynomial equation?
irga5000 [103]

Answer:

-4, -2, -3-2i, -3+2i

Step-by-step explanation:

The of the polynomial equation are those values of x, for which f(x)=0.

Consider equation

f(x)=0\\ \\(x^2+6x+8)(x^2+6x+13)=0

By zero product property,

x^2+6x+8=0\ \text{or}\ x^2+6x+13=0

Solve each equation:

1. x^2+6x+8=0

D=6^2-4\cdot 8=36-32=4\\ \\x_{1,2}=\dfrac{-6\pm \sqrt{4}}{2}=\dfrac{-6\pm 2}{2}=-4,\ -2

2. x^2+6x+13=0

D=6^2-4\cdot 13=36-52=-16=16i^2\\ \\x_{1,2}=\dfrac{-6\pm \sqrt{16i^2}}{2}=\dfrac{-6\pm 4i}{2}=-3-2i,\ -3+2i

5 0
3 years ago
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I’m giving out brainlest to whoever answers this correctly!
borishaifa [10]

Answer:

A. 18.2

Step-by-step explanation:

b^2 + 14^2 = 23^2

b = sqrt(333) = 18.248

5 0
3 years ago
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