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Anuta_ua [19.1K]
3 years ago
8

Two rectangular prisms have the same volume. The area of the base, B, of the blue prism is 418 square units. The area of the bas

e, B, of the red prism is half that of the blue prism. Which statement is true?
A. The height of the red prism is half the height of the blue prism.
B. The height of the red prism is the same as the height of the blue prism.
C. The height of the red prism is twice the height of the blue prism.
D. The height of the red prism is four times the height of the blue prism.
Mathematics
1 answer:
MakcuM [25]3 years ago
3 0

your answer would be a because the question was be of the blue prism 418 square units the area of the base B of the red prism is half that of blue. a would be right the height of the red prism is half of the height of blue
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Data was collected for 300 fish from the North Atlantic. The length of the fish (in mm) is summarized in the GFDT below.
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Answer:

The lower class boundary for the first class is 140.

Step-by-step explanation:

The variable of interest is the length of the fish from the North Atlantic. This variable is quantitative continuous.

These variables can assume an infinite number of values within its range of definition, so the data are classified in classes.

These classes are mutually exclusive, independent, exhaustive, the width of the classes should be the same.

The number of classes used is determined by the researcher, but it should not be too small or too large, and within the range of the variable. When you decide on the number of classes, you can determine their width by dividing the sample size by the number of classes. The next step after getting the class width is to determine the class intervals, starting with the least observation you add the calculated width to get each class-bound.

The interval opens with the lower class boundary and closes with the upper-class boundary.

In this example, the lower class boundary for the first class is 140.

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Read 2 more answers
Number 12.
const2013 [10]

D

given the 2 equations

x + 2y = - 8 → (1)

- 4x + y = 5 → (2)

multiply (1) by 4

4x + 8y = - 32 → (3)

add (2) and (3) term by term to eliminate term in x

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substitute y = - 3 in either (1) or (2) and solve for x

(1) : x - 6 = - 8 ( add 6 to both sides )

x = - 2

solution is (- 2, - 3 ) → D


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