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Anuta_ua [19.1K]
3 years ago
8

Two rectangular prisms have the same volume. The area of the base, B, of the blue prism is 418 square units. The area of the bas

e, B, of the red prism is half that of the blue prism. Which statement is true?
A. The height of the red prism is half the height of the blue prism.
B. The height of the red prism is the same as the height of the blue prism.
C. The height of the red prism is twice the height of the blue prism.
D. The height of the red prism is four times the height of the blue prism.
Mathematics
1 answer:
MakcuM [25]3 years ago
3 0

your answer would be a because the question was be of the blue prism 418 square units the area of the base B of the red prism is half that of blue. a would be right the height of the red prism is half of the height of blue
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Giving brainliest *easy*!!
Norma-Jean [14]

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In the regular pentagon below, if AP = 4 m and BC = 10 m, find it's area.
12345 [234]

First symmetrically cut the pentagon to get 5 pieces. (So that you will get the idea that this polygon is divided into 5 triangles)

Then find the area of one of the triangles:

Area of Triangle = \frac{1}{2} bh

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To find the area of the whole pentagon shape:

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4 0
2 years ago
0.134 bar in the form of p/q​
kenny6666 [7]

Answer:

67/500

Step-by-step explanation:

we have

The decimal number 0.134

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3 years ago
When 2(3/5 x + 2/3 y - 1/4 x -1 1/2 y + 3 )is simplified, what is the resulting expression?
vovangra [49]

Answer:

Simplifying  the expression: 2(\frac{3}{5}x+\frac{2}{3}y-\frac{1}{4}x-1\frac{1}{2}y +3) we get \mathbf{42x-100y-360}

Step-by-step explanation:

We need to simplify the expression: 2(\frac{3}{5}x+\frac{2}{3}y-\frac{1}{4}x-1\frac{1}{2}y +3)

First we will solve terms inside the bracket

2(\frac{3}{5}x+\frac{2}{3}y-\frac{1}{4}x-1\frac{1}{2}y +3)

Converting mixed fraction 1\frac{1}{2} y into improper fraction, we get: \frac{3}{2}y

Replacing the term:

2(\frac{3}{5}x+\frac{2}{3}y-\frac{1}{4}x-\frac{3}{2}y +3)

Now, taking LCM of: 5,3,4,2 we get 60

Now multiply 60 with each term inside the bracket

2(\frac{3}{5}x\times60+\frac{2}{3}y\times60-\frac{1}{4}x\times60-\frac{3}{2}y\times60 +3\times60)\\2(3x\times12+2y\times20-1x\times15-3x\times30-3\times60)\\2(36x+40y-15x-90y-180)

Now, combine like terms

2(36x-15x-90y+40y-180)\\2(21x-50y-180)

Now, multiply all terms with 2

42x-100y-360

So, Simplifying  the expression: 2(\frac{3}{5}x+\frac{2}{3}y-\frac{1}{4}x-1\frac{1}{2}y +3) we get \mathbf{42x-100y-360}

3 0
3 years ago
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