I will mark brainlist!!

Mathematics

2 answers:

Fudgin [204]3 years ago

7 0

Answer:

3/5 + 2 3/4 = 3 7/20

Step-by-step explanation:

2 = 8/4

2 3/4 = 2 + 3/4

then:

3/5 + 2 3/4 = 3/5 + 8/4 + 3/4

= 3/5 + (8+3)/4

= 3/5 + 11/4

3/5 = 12/20

11/4 = 55/20

then:

3/5 + 11/4 = 12/20 + 55/20 = 67/20

67/20 = 60/20 + 7/20 = 3 + 7/20

= 3 7/20

LenKa [72]3 years ago

4 0

3/5 + 2 3/4
= 3/5 + 11/4
= 12/20 + 55/20
= 67/20
= 3 7/20

You might be interested in

Establish each identity:<br> csc Θ/ 1+ csc Θ = 1-sin Θ/ cos^2 Θ

shtirl [24]

$sin^2(\theta)+cos^2(\theta)=1\implies cos^2(\theta)=1-sin^2(\theta) \\\\[-0.35em] \rule{34em}{0.25pt}$

$\cfrac{csc(\theta )}{1+csc(\theta )}=\cfrac{1-sin(\theta )}{cos^2(\theta )} \\\\[-0.35em] ~\dotfill\\\\ \cfrac{csc(\theta )}{1+csc(\theta )}\implies \cfrac{~~\frac{1}{sin(\theta )} ~~}{1+\frac{1}{sin(\theta )}}\implies \cfrac{~~\frac{1}{sin(\theta )} ~~}{\frac{sin(\theta )+1}{sin(\theta )}}\implies \cfrac{1}{sin(\theta )}\cdot \cfrac{sin(\theta )}{sin(\theta )+1}$

$\cfrac{1}{sin(\theta )+1}\implies \cfrac{1}{1+sin(\theta )}\implies \stackrel{\textit{multiplying by the conjugate of the denominator}}{\underset{\textit{difference of squares}}{\cfrac{1}{1+sin(\theta )}\cdot \cfrac{1-sin(\theta )}{1-sin(\theta )}}} \\\\\\ \cfrac{1-sin(\theta )}{1^2-sin^2(\theta )}\implies \cfrac{1-sin(\theta )}{1-sin^2(\theta )}\implies \cfrac{1-sin(\theta )}{cos^2(\theta )}$