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Zarrin [17]
3 years ago
11

-3x-ly = -16 2x +1y = 11

Mathematics
2 answers:
Aleksandr [31]3 years ago
5 0

Answer: (-2/15, -53/5)

Step-by-step explanation:

multiply, simplify, thn rimate the one variable by adding the equations then divide sides by -165 then substitute

MAVERICK [17]3 years ago
5 0

Answer:

x = 5 ;  y =1

Step-by-step explanation:

  -3x - 1y = -16   ----------(i)

  <u> 2x + 1 y= 11</u>  ---------(ii)  {add (i) and (ii), +1y and -1y will be eliminated}

   -x         = -5

divide both side by -1

\frac{-x}{-1}=\frac{-5}{-1}

x = 5

Plug in x = 5 in (i)

-3*5 - 1y = -16

-15 - y = -16

-y = -16 + 15

-y = -1

divide both side by (-1)

\frac{-y}{-1}=\frac{-1}{-1}\\y = 1

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the utilities bill for the Miller's' house in April was $132. forty two percent of the bill was for gas, and the rest was for el
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132*42% = 55.44

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Read 2 more answers
Peregrine falcons can dive at speeds of up to 217 miles per hour. Use dimensional analysis to convert this speed to feet per min
RSB [31]

The speed 217 miles per hour using dimensional analysis to convert to feet per minute is; 19096 ft/min

<h3>How to use Dimensional Analysis?</h3>

From dimensional analysis, we know that;

1  mile = 5280 feet

1 hour = 60 minutes

Thus;

1 mile/hr = 88 feet/min

Since conversion from mph to ft/min is, 1 mile/hr = 88 feet/min

Then, 217 mile/hr = (217 mile/hr/1 mile/hr) * 88 feet/min

⇒ 19096 ft/min

Read more about Dimensional Analysis at; brainly.com/question/20712353

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3 0
3 years ago
Anyone know this?i need help
belka [17]

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Step-by-step explanation:

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6 0
3 years ago
In 2002, Tim was twice as old as Sue. In 1997 the sum of their ages was 32. In what year will Sue's age be three-fourths Tim's a
xxMikexx [17]

Answer:

Year 2030.

Step-by-step explanation

In 1997, Let Tim's age = <em>X</em> years

In 1997, Let Sue's age = <em>Y</em> years

After 5 years in 2002, Tim's age = (<em>X+ 5) </em>years

After 5 years in 2002, Sue's age = <em>(Y + 5)</em> years

Now, According to question,

<em>X </em>+ <em>Y</em> = 32    (sum of their ages) .......(1)

<em>Y </em>= 32 -<em> X</em>

(X + 5) = 2 (Y + 5) .......(2)

Substituting the value of <em>Y</em> in (2)

<em>X </em>+ 5 = 2 (32 - <em>X </em>+ 5)

<em>X </em>+ 5 = 2 (37 - <em>X </em>)

<em>X </em>+ 5 = 74 - 2<em>X </em>

3<em>X </em>=<em> </em>69

<em>X </em>= 69/3 = 23

Now ∵<em> Y</em> = 32 - <em>X  </em>and<em> X = </em>23

∴ <em>Y</em> = 32 - 23 = 9

So, In 1997, Tim's age = 23 years and Sue's age = 9 years.

Let the year in which Sue's age will be three-fourth times of Tim's age be t.

Sue's age after<em> t </em>years = (9 +<em> t) </em>years.

Tim's age after<em> t</em> years = (23 + <em>t</em>) years

According to question,

(9 + t) = \frac{3}{4} \times(23 + t)

4 (9 + t) = 3 (23 + t)

36 + 4t = 69 + 3t

<em>4t - 3t = 69 - 36</em>

<em>t = 33</em>

The Year in which Sue's age will be three-fourth times of Tim's age is:

= (1997 + 33) = 2030.

4 0
4 years ago
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