Simplify the expression using the disproperty rule. -2(3÷9x)=

Question 9 of 10 Which of these groups of values plugged into the TVM Solver of a graphing calculator will return the same value

hodyreva [135]

The TVM solver is a tool found in graphing calculators, that solve Time Value of Money problems.

The group of values that will return the same value as the given expression is;

D. N = 24; I% = 3.6; PV =; PMT = -415; FV = 0; P/Y = 12; C/Y = 12; PMT :END

<h3>What is Present Value?</h3>

Present value (PV) formula finds application in finance to calculate the present day value of an amount that is received at a future date.

In the TVM solver, we have;

I = The annual percentage rate

N = n × t

t = The number of years

PV = Present value

PMT = Payment

P/Y = Number of payments per year = n

C/Y = Number of compounding periods per year = n

The formula for monthly payment is presented as follows;

$P = \frac{M[(1+r/n)^{nt} - 1]}{(r/n)(1+r/n)^{nt}}$

M = $\frac{P.(r/n)(1+ r/n)^{nt} }{(1+ r/n)^{nt} - 1}$

Therefore, we get;

Where;

M = PMT = -415

P = PV

r = I

P/Y = n = 12

Therefore;

0.003 = I/12

I = 0.003 X 12 = 3.6%

N = n X t = 24

The value of the equation is the present value, PV = ?

When payment are made based on the PV, we have FV = 0

The group of values the same value as the expression

P = $\frac{(415)[(1+0.003)^{24}-1]}{(0.003)(1+0.003)^{24}}$

when plugged into the TVM solver of a calculator is;

D. N = 24; I% = 3.6; PV =; PMT = -415; FV = 0; P/Y = 12; C/Y = 12; PMT :END

Learn more about Present Value Solver from:

brainly.com/question/1759639

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7 0

2 years ago

Math question down below need answers for a b c and d please

storchak [24]

(a). How much the T-shirt cost.
(b). 23=12+x
(c). 23-12=x; x= 11
(d) the T-shirt cost $11.

6 0

3 years ago

<img src="https://tex.z-dn.net/?f=%20%5Crm%20%5Cint_%7B0%7D%5E%7B%20%20%5Cpi%20%7D%20%5Ccos%28%20%5Ccot%28x%29%20%20%20%20-%20%2

Nikolay [14]

Replace x with π/2 - x to get the equivalent integral

$\displaystyle \int_{-\frac\pi2}^{\frac\pi2} \cos(\cot(x) - \tan(x)) \, dx$

but the integrand is even, so this is really just

$\displaystyle 2 \int_0^{\frac\pi2} \cos(\cot(x) - \tan(x)) \, dx$

Substitute x = 1/2 arccot(u/2), which transforms the integral to

$\displaystyle 2 \int_{-\infty}^\infty \frac{\cos(u)}{u^2+4} \, du$

There are lots of ways to compute this. What I did was to consider the complex contour integral

$\displaystyle \int_\gamma \frac{e^{iz}}{z^2+4} \, dz$

where γ is a semicircle in the complex plane with its diameter joining (-R, 0) and (R, 0) on the real axis. A bound for the integral over the arc of the circle is estimated to be

$\displaystyle \left|\int_{z=Re^{i0}}^{z=Re^{i\pi}} f(z) \, dz\right| \le \frac{\pi R}{|R^2-4|}$