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IRINA_888 [86]
3 years ago
11

If cats prowl, mice will scatter. Mice are scattering

Mathematics
1 answer:
Nadusha1986 [10]3 years ago
8 0
The cat prowled and the mice scattered
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In a circle a 90 degrees sector has an area of 36 square inches what is the radius of the cirlce
Gelneren [198K]
The answer would be 12 (fixed to your answers)
6 0
4 years ago
1. The mechanics at Lincoln Automotive are reborning a 6 in deep cylinder to fit a new piston. The machine they are using increa
Firdavs [7]

Answer:

0.0239\frac{in^{3}}{min}

Step-by-step explanation:

In order to solve this problem, we must start by drawing a diagram of the cylinder. (See attached picture)

This diagram will help us visualize the problem better.

So we start by determining what data we already know:

Height=6in

Diameter=3.8in

Radius = 1.9 in (because the radius is half the length of the diameter)

The problem also states that the radius will increase on thousandth of an inch every 3 minutes. We can find the velocity at which the radius is increasing with this data:

r'=\frac{1/1000in}{3min}

which yields:

r'=\frac{1}{3000}\frac{in}{min}

with this information we can start solving the problem.

First, the problem wants us to know how fast the volume is increasing, so in order to find that we need to start with the volume formula for a cylinder, which is:

V=\pi r^{2}h

where V is the volumen, r is the radius, h is the height and π is a mathematical constant equal approximately to 3.1416.

Now, the height of the cylinder will not change at any time during the reborning, so we can directly substitute the provided height, so we get:

V=\pi r^{2}(6)

or

V=6 \pi r^{2}

We can now take the derivative to this formula so we get:

\frac{dV}{dt}=2(6)\pi r \frac{dr}{dt}

Which simplifies to:

\frac{dV}{dt}=12\pi r \frac{dr}{dt}

We can now substitute the data provided by the problem to get:

\frac{dV}{dt}=12\pi (1.9) (\frac{1}{3000})

which yields:

\frac{dV}{dt}=0.0239\frac{in^{3}}{min}

3 0
4 years ago
6. 18% of people in
Advocard [28]
18%=
18 / 100
0.18

Hope it helps
Brainliest would be nice:)
3 0
3 years ago
What us the midpoint of A(-8,2) and B(4,-2)​
marusya05 [52]

Answer:

(-2 , 2)

Step-by-step explanation:

A(-8 , 2) = (x1 , y1)

B(4 , -2) = (x2 , y2)

midpoint = (x1 + x2/2  ,   y1 + y2/2)

=(-8 + 4/2  ,  2-(-2)/2)

=(-4/2  ,  2+2/2)

(-2  ,  2)

(3 , 7) = (x1 , y1)

(9 , 2) = (x2 , y2)

distance of PQ = \sqrt{(x2 - x1)^2 + (y2 - y1)^2}

=\sqrt{(9 - 3)^2 + (2 - 7)^2}

=\sqrt{(6)^2 + (-5)^2}

=\sqrt{36 + 25}

=\sqrt{61}

=7.8 unit

4 0
3 years ago
I need help again...help??
Tasya [4]

Answer:

x ≥14

Closed circle at 14 line to the right

x≤3

closed circle at 3  line to the left

Step-by-step explanation:

(x-4)/5 ≥2

Multiply by 5

(x-4 )/5 *5 ≥2 *5

x-4 ≥10

Add 4 to each side

x-4+4≥10+4

x ≥14

Closed circle at 14 line to the right

3x-4 ≤5

Add 4 to each side

3x-4 +4≤5+4

3x  ≤9

Divide by 3

3x/3  ≤9/3

x≤3

closed circle at 3  line to the left

5 0
3 years ago
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