7 > z + 18 ≥ 6
Subtract 18 from all 3 parts:
7-18 > z +18 -18 ≥ 6-18
-11 > z ≥ -12
Answer:
Step-by-step explanation:
<span>a) Differentiate both sides of lnq − 3lnp + 0.003p=7 with respect to p, keeping in mind that q is a function of p and so using the Chain Rule to differentiate any functions of q:
(1/q)(dq/dp) − 3/p + 0.003 = 0
dq/dp = (3/p − 0.003)q.
So E(p) = dq/dp (p/q) = (3/p − 0.003)(q)(p/q) = (3/p − 0.003)p = 3 − 0.003p.
b) The revenue is pq.
Note that (d/dp) of pq = q + p dq/dp = q[1 + dq/dp (p/q)] = q(1 + E(p)), which is zero when E(p) = −1. Therefore, to maximize revenue, set E(p) = −1:
3 − 0.003p = −1
0.003p = 4
p = 4/0.003 = 4000/3 = 1333.33</span>
Answer:
Step-by-step explanation:
V= <em>lwh</em><em> </em>or <em>l</em><em> </em><em>*</em><em>w</em><em>*</em><em>h</em>
<em>Length</em><em>:</em><em> </em><em>15</em>
<em>Width</em><em>:</em><em> </em><em>3</em>
<em>Height</em><em>:</em><em>4</em>
<em>V</em><em>=</em><em>15</em><em>*</em><em>3</em><em>*</em><em>4</em>
V=180
Answer:
190 games
Step-by-step explanation:
²⁰C₂ = 20!/[(20 - 2)! * 2!] = 190
