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Vikentia [17]
3 years ago
7

A car moving at a constant speed passed a timing device at t = 0. After 8 seconds, the car has

Mathematics
1 answer:
maksim [4K]3 years ago
5 0

Answer:answer d

Step-by-step explanation:

i just did the test

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I need help on this problem will give Brainlist if right!
Sindrei [870]

Answer:

b

Step-by-step explanation:

7 0
3 years ago
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Find the given derivative by finding the first few derivatives and observing the pattern that occurs. d103 dx103 (sin(x))
aleksandrvk [35]
To find \frac{d^{103}}{dx^{103}} \left(\sin{(x)}\right), we find the first few derivatives and observe the pattern that occurs.

\frac{d}{dx} (\sin{(x)})=\cos{(x)} \\  \\  \frac{d^2}{dx^2} (\sin{(x)})= \frac{d}{dx} (\cos{(x)})=-\sin{(x)} \\  \\ \frac{d^3}{dx^3} (\sin{(x)})= -\frac{d}{dx} (\sin{(x)})=-\cos{(x)} \\  \\ \frac{d^4}{dx^4} (\sin{(x)})= -\frac{d}{dx} (\cos{(x)})=-(-\sin{(x)})=\sin{(x)} \\  \\ \frac{d^5}{dx^5} (\sin{(x)})=  \frac{d}{dx} (\sin{(x)})=\cos{(x)}

As can be seen above, it can be seen that the continuos derivative of sin (x) is a sequence which repeats after every four terms.

Thus,

\frac{d^{103}}{dx^{103}} \left(\sin{(x)}\right)= \frac{d^{4(25)+3}}{dx^{4(25)+3}} \left(\sin{(x)}\right) \\  \\ = \frac{d^3}{dx^3} \left(\sin{(x)}\right)=-\cos{(x)}

Therefore,

\frac{d^{103}}{dx^{103}} \left(\sin{(x)}\right)=-\cos{(x)}.
8 0
3 years ago
if a shape is a regular pentagon with five sides, which of the following must be true? Check all that apply
julsineya [31]

Answer:

A. It has reflectional symmetry

B. It is symmetrical

D. It has five lines of symmetry

Step-by-step explanation:

we know that

A regular pentagon has 5 sides and 5 lines of symmetry. The number of lines of symmetry in a regular polygon is equal to the number of sides

Every regular polygon has reflectional symmetry

Regular polygons are symmetrical

therefore

A. It has reflectional symmetry ------> Is true

B. It is symmetrical -----> Is true

C. It has exactly one line of symmetry ----> Is false

D. It has five lines of symmetry -----> Is true

4 0
3 years ago
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¿se puede hacer un triangulo con las siguientes medidas:2cm ,3cm ,10cm? ayudenme es para mañana
dezoksy [38]

Não, não podemos fazer um triângulo com os comprimentos dos lados de 2 cm, 3 cm e 10 cm. Isso ocorre porque a soma de 2+3 < 10. (in english: No, we cannot make a triangle with the side lengths of measurement 2 cm, 3 cm, and 10 cm. This is because sum of 2+3 < 10).

<h3>What is triangle inequality theorem?</h3>

Triangle inequality theorem of a triangle says that the sum of any of the two sides of a triangle is always greater than the third side.

Suppose a, b and c are the three sides of a triangle. Thus according to this theorem,

(a+b) > c\\(b+c) > a\\(c+a) > b

Now, for this case, the sides given are:

  • a =2 cm,
  • b = 3 cm,
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But we see that:

a+ b = 5 cm which is < c which is of 10 cm.

Thus, these lengths don't satisfy the triangle inequality theorem, and therefore, cannot be sides of any triangle.

Learn more about triangle inequality theorem here:

brainly.com/question/342881

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3 0
3 years ago
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Y=a(1+r)^x growth formula
y=a(1-r)^x decay formula
a = amount 
r = percentage rate
x = time in years 

4 0
3 years ago
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