What's the answer? Plz explain.
1 answer:
From the V-shape of the graph, we see that the base function is an absolute value function, or
y=|x|.
The slope of each arm is ± (10-5)/5 = 2, so
the function with the vertex at origin is y=2|x|.
To move the vertex to the RIGHT by 5 units, we replace x by x-5, or
y=2|x-5|
We are given this function equals h(x)-5, or
h(x)-5 = 2|x-5|
solving for h(x) gives
h(x)=2|x-5|+5 (red curve)
We are also told that h(x) is a reflection about the y-axis, i.e.
f(x)=h(-x)
=2|-x-5|+5
=2|x+5|+5 because |X+A|=|-X-A|
which is the green line shown in the attached graph.
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Answer:
The liters that the tank will contain at 5:11 PM that day are:
- <u>4416 Liters</u>.
Step-by-step explanation:
Firstly, you must identify the outlet flow of the water pumped from the tank, for this, you must subtract the last volume given from the first volume:
- 19,140 L - 8,097 L = 11,043 L
And the minutes that passed from the first volume until the last volume given (18 minutes from 4:47 PM to 5:05 PM), so, you must divide that two values to obtain the outlet flow:
- Outlet flow =
- Outlet flow =
- Outlet flow = 613.5
Now, you must see the next hour given (5:11 PM), if you see, from 5:05 PM to 5:11 PM has passed 6 minutes, taking into account this, you replace the equation of outlet flow to clear the volume:
- Outlet flow =
- Volume = Outlet flow * time
And replace the values to obtain the new volume pumped:
- Volume = 613.5
* 6 min
- Volume = 3681 L.
At last, you must subtract these liters from the last volume identified in the tank:
- New Volume in the tank = 8097 L - 3681 L
- New Volume in the tank = 4416 L
The volume in the tank at 5:11 PM is <u>4416 Liters</u>.