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velikii [3]
3 years ago
11

What is the final answer?

Mathematics
2 answers:
Phantasy [73]3 years ago
3 0
4 bc I’m smart and I passed
gogolik [260]3 years ago
3 0
It’s 4 I did it too :)
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How do you verify this trigonometric identity? cos^2 θcot^2 θ = cot^2 θ - cos^2 θ
sattari [20]
<h3>Explanation:</h3>

Replace cos^2(θ) with 1-sin^2(θ), and cot(θ) with cos(θ)/sin(θ).

  cos^2(θ)cot^2(θ) = cot^2(θ) - cos^2(θ)

  (1 -sin^2(θ))cot^2(θ) =  . . . . . replace cos^2 with 1-sin^2

  cot^2(θ) -sin^2(θ)·cos^2(θ)/sin^2(θ) = . . . . . replace cot with cos/sin

  cot^2(θ) -cos^2(θ) = cot^2(θ) -cos^2(θ) . . . as desired

8 0
3 years ago
About how many times does a chickens heart beat in 1. Min
sammy [17]
Hello, a chickens heart beats 280-315 times per minute.

Happy Studies <3

8 0
3 years ago
Read 2 more answers
Since 2010, when 102390 Cases were reported, each year the number of new flu cases decrease to 85% of the prior year. Predict th
BaLLatris [955]

Answer:

20,158 cases

Step-by-step explanation:

Let t=0 represent year 2010.

We have been given that since 2010, when 102390 Cases were reported, each year the number of new flu cases decrease to 85% of the prior year.

Since the flu cases decrease to 85% of the prior year, so the flu cases for every next year will be 85% of last year and decay rate is 15%.

We can represent this information in an exponential decay function as:

F(t)=102,390(1-0.15)^t

F(t)=102,390(0.85)^t

To find number of cases in 2020, we will substitute t=10 in our decay function as:

F(10)=102,390(0.85)^{10}

F(10)=102,390(0.1968744043407227)

F(10)=20,157.970260446597\approx 20,158

Therefore, 20,158 cases  will be reported in 2020.

3 0
3 years ago
The measurement of the height of 600 students of a college is normally distributed with a mean of
ioda

Answer:

68

Step-by-step explanation:

We let the random variable X denote the height of students of the college. Therefore, X is normally distributed with a mean of 175 cm and a standard deviation of 5 centimeters.

We are required to determine the percent of students who are between 170 centimeters and 180 centimeters in height.

This can be expressed as;

P(170<X<180)

This can be evaluated in Stat-Crunch using the following steps;

In stat crunch, click Stat then Calculators and select Normal

In the pop-up window that appears click Between

Input the value of the mean as 175 and that of the standard deviation as 5

Then input the values 170 and 180

click compute

Stat-Crunch returns a probability of approximately 68%

5 0
3 years ago
Solve the problem <br> -5(x-4)=-30<br><br><br><br><br> By Random Questions
notsponge [240]
-5(x-4)=-30
-5x - -20=-30
-5x+20=-30
      -20   -20
-5x=-50
divide both sides by -5
x=10
6 0
3 years ago
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