2x^2 + 2y^2 + 2xy I think
Answer:
P43=4!(4–3)!=241=24
Step-by-step explanation:
There are four choices you can make for the lead reindeer. For each possible choice, there are then three remaining you can choose to fly second, making 4×3=12 choices for the lead pair. For each possible choice there are two remaining reindeer to take up the back position, making 12×2=24 choices for the team of three.
This type of problem is called a permutation problem, and we write Pnr for the number of ways of choosing r items from n possibilities when the order of the items matters. In this case we are choosing 3 reindeer from 4 possibilities, and the order they appear in the flying line does matter, so the answer we want is P43. The general formula is Pnr=n!(n−r)!. For the answer we are looking for we therefore have:
P43=4!(4–3)!=241=24
<span>He is budgeting too much for transportation.
He has used the highest recommended percentages to calculate the amounts for the three categories.
He is budgeting too much for housing.
He has used the lowest recommended percentages to calculate the amounts for the three categories. hope this helps :)</span>
14/20=0.7 or 70% are soft-centred. If we take two candies we have three possibilities associated with probabilities:
Both soft-centred: 0.7²=0.49 or 49%
Both hard-centred: 0.3²=0.09 or 9%
One of each: 2×0.3×0.7=0.42 or 42%. 49+9+42=100%. So these are all the possible outcomes.
<u>Answer:</u>
355 senior citizen tickets were sold.
<u>Step-by-step explanation:</u>
Assuming a to the the ticket of adults and s to be the ticket of senior citizens, we can write two equations as:
--- (1)
--- (2)
From equation 1, 
.
Substitute 
in equation 2 to get:
Therefore, there were 355 senior citizen tickets sold.
