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Finger [1]
3 years ago
12

Pls help - Solve for x​

Mathematics
1 answer:
Stels [109]3 years ago
5 0

Answer:

-3

3x/(x^2+6x) = 1 is this the qstn?

if so then the ans is -3

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Determine whether the function f(x)=4x^3 is even or odd
slega [8]

Answer:

Step-by-step explanation:

Answer:

odd function

Explanation:

   To determine if a function f(x) is even/odd consider the following.

   • If f(x) = f( -x) , then f(x) is even

   Even functions are symmetrical about the y-axis.

   • If - f(x) = f(-x) , then f(x) is odd

   Odd functions have symmetry about the origin.

   Test for even function

   f(−x)=4(−x)3=−4x3≠f(x)

   Since f(x) ≠ f( -x) , then f(x) is not even

   Test for odd function

   −f(x)=−(4x3)=−4x3=f(−x)

   Since - f(x) = f( -x) , then f(x) is odd

   graph{4x^3 [-10, 10, -5, 5]}

 

7 0
3 years ago
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Pls Help I need this in soon and am stuck, am giving out 25 points
Sergio039 [100]

Answer:

12

Step-by-step explanation:

7 0
3 years ago
Which ratio is equivalent to 2:8
Serhud [2]
1:4 is equal to 2:8, it's a simplified version.
6 0
3 years ago
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Mark was able to save $800 in 5 weeks. At the same rate, how much could he save in 8 weeks?
Vilka [71]

Answer:

<h2>$1,280</h2>

Step-by-step explanation:

Since the rate is constant, we can do the following method.

\frac{800dollars}{5 weeks} = $160 is saved per week.

Now, multiply the amount of money for 1 week by 8.

$160 × 8 = $1,280

<em>I hope this helps! I would really appreciate it if you would please make me brainliest! Have a blessed day!</em>

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5 0
3 years ago
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The figure below shows two triangles EFG and KLM.
grandymaker [24]

A right triangle is a triangle that has a right angle of 90 degrees. In this exercise, we have two of this type of triangles. To solve this problem, we will apply some properties of triangles, so:


1. Which step can be used to prove that triangle EFG is also a right triangle?

To prove this, we need to use Pythagorean Theorem. So, for triangle EGF, if the formula:

c^{2}=a^{2}+b^{2}

is true, then EFG is also a right triangle. The steps are:

  • Square a
  • Square b
  • Square c
  • If the sum of the square of a and the sum of the square of b equals the square of c, then this is a right triangle.

2. Prove that the sum of a and c is greater than b.

We need to prove that:

a+c>b


From trigonometry, we know that:

a=c \times sin(\theta) \\ \\ b=c \times cos(\theta) \\ \\ where \ \theta=\angle EFG \\ \\


By substituting these values in the previous inequality:

c \times sin(\theta)+c>c \times cos(\theta) \\ \\ Since \ c>0 \\ \\ sin(\theta)+1>cos(\theta) \\ \\ 1>cos(\theta)-sin(\theta)


Since \theta is an angle greater than 0 and less than 90 degrees, cos(\theta) \ and \ sin(\theta) are numbers between 0 (greater than) and 1. Therefore, this inequality is always true. So, the statement has been proved.


3. Prove that the sum of a and b is greater than c.

We need to prove that:

a+b>c


Applying the same reasoning as in 2:

c \times sin(\theta)+c \times cos(\theta)>c \\ \\ Since \ c>0 \\ \\ sin(\theta)+cos(\theta)>1


This inequality is always true. So, the statement has been proved.


4. Prove that triangles are congruent by SSS property and hence angle EGF is equal to angle KML.


SSS means that we know the three sides of the triangle and want to find the missing angles. For ΔEGF, we know the three sides, and for KML, since this is a right triangle KL = c, therefore the corresponding sides of these two triangles are equal. Accordingly, these two triangles are congruent by SSS and angle EGF is equal to angle KML.


5. Prove that the ratio of EF and KL is greater than 1 and hence the triangles are similar by AA postulate.


The ratio of EF and KL is:

\frac{EF}{KL}

The statement is true if and only if EF > KL. Then, according to AA postulate, two triangles are similar if they have two corresponding angles congruent. So:


  • EGF is congruent to KML and equals 90 degrees
  • GEF is congruent to MKL
  • EFG is conguent to KLM

Accordingly, the triangles are similar.

3 0
3 years ago
Read 2 more answers
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