Answer:
432? I cannot tell if x is multiplication or a variable
Step-by-step explanation:
The domain of a graph is the possible values of x, the graph can take.
<em>(b) The domain of the relation is the interval [-10,10]</em>
From the attached graph, we have the following observations on the x-axis.
- <em>The value of x starts from -10</em>
- <em>The value of x ends at 10</em>
So, the domain of x is from -10 to 10
Using interval notation, the domain of the relation is: ![[-10,10]](https://tex.z-dn.net/?f=%5B-10%2C10%5D)
Read more about domains at:
brainly.com/question/16875632
Answer:
-19 y^2 + 18 x y + 13 x^2
Step-by-step explanation:
Simplify the following:
16 x^2 + 15 x y - 19 y^2 - (3 x^2 - 3 x y)
Factor 3 x out of 3 x^2 - 3 x y:
16 x^2 + 15 x y - 19 y^2 - 3 x (x - y)
-3 x (x - y) = 3 x y - 3 x^2:
16 x^2 + 15 x y - 19 y^2 + 3 x y - 3 x^2
Grouping like terms, 16 x^2 + 15 x y - 19 y^2 - 3 x^2 + 3 x y = -19 y^2 + (15 x y + 3 x y) + (16 x^2 - 3 x^2):
-19 y^2 + (15 x y + 3 x y) + (16 x^2 - 3 x^2)
x y 15 + x y 3 = 18 x y:
-19 y^2 + 18 x y + (16 x^2 - 3 x^2)
16 x^2 - 3 x^2 = 13 x^2:
Answer: -19 y^2 + 18 x y + 13 x^2
Answer: The answer is 381.85 feet.
Step-by-step explanation: Given that a window is 20 feet above the ground. From there, the angle of elevation to the top of a building across the street is 78°, and the angle of depression to the base of the same building is 15°. We are to calculate the height of the building across the street.
This situation is framed very nicely in the attached figure, where
BG = 20 feet, ∠AWB = 78°, ∠WAB = WBG = 15° and AH = height of the bulding across the street = ?
From the right-angled triangle WGB, we have

and from the right-angled triangle WAB, we have'

Therefore, AH = AB + BH = h + GB = 361.85+20 = 381.85 feet.
Thus, the height of the building across the street is 381.85 feet.