The blanks in this two-column proof should be filled as follows:
<u>Statements Reasons</u>_______________
m∠1 = m∠3 Given
m∠CBA = m∠ABE + m∠CBD Angle Addition Postulate
m∠ABE = m∠3 + m∠2 Substitution Property of Equality
m∠CBD = m∠3 + m∠2 Substitution Property of Equality
m∠ABE ≅ m∠CBD Transitive Property of Equality
<h3>What is the Angle Addition Postulate?</h3>
In Mathematics, the Angle Addition Postulate states that the measure of an angle formed by two (2) angles that are placed side by side to each other is equal to the sum of the measures of the two (2) angles.
This ultimately implies that, the Angle Addition Postulate can be used to determine the measurement of a missing angle in a geometric figure or it can be used for calculating an angle that is formed by two (2) or more angles such as m∠CBA = m∠ABE + m∠CBD.
Read more on Angle Addition Postulate here: brainly.com/question/24746945
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You use the quadratic formula:
2x {}^{2} - 3x = 5
2x {}^{2} - 3x - 5 = 0
x = \frac{3 + - \sqrt{9 -4(2)( - 5)}}{2 \times 2}
x = \frac{3 + - \sqrt{49} }{4}
x = \frac{3 + 7}{4} \: and \: x = \frac{3 - 7}{4}
x = \frac{5}{2} \: and \: x = - 1
Answer: 272.85
(It’s 21.4 times 12.75)
Answer:
The 99% confidence interval of the population mean for the weights of adult elephants is between 12,475 pounds and 12,637 pounds.
Step-by-step explanation:
We have the standard deviation for the sample, so we use the t-distribution to solve this question.
The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So
df = 10 - 1 = 9
99% confidence interval
Now, we have to find a value of T, which is found looking at the t table, with 9 degrees of freedom(y-axis) and a confidence level of 
. So we have T = 3.25
The margin of error is:
M = T*s = 3.25*25 = 81
In which s is the standard deviation of the sample.
The lower end of the interval is the sample mean subtracted by M. So it is 12,556 - 81 = 12,475 pounds
The upper end of the interval is the sample mean added to M. So it is 12,556 + 81 = 12,637 pounds.
The 99% confidence interval of the population mean for the weights of adult elephants is between 12,475 pounds and 12,637 pounds.
