Question

The John Hancock Center in Chicago is the tallest in the United state's in which there are residential apartments. The Hancock center is 343m tall. Suppose a resident accidentally causes a chuck of ice to fall from the roof. What would be the velocity of the ice as it hits the ground? Neglect air resistance.

Answer 1

The final velocity of the ice is 82.0 m/s

Explanation:

The chuck of ice in this problem is in free fall, so we can use the following suvat equation for uniformly accelerated motion:

$v^2-u^2=2as$

where

v is the final velocity

u is the initial velocity

a is the acceleration

s is the displacement

In this problem, we have:

u = 0 is the initial velocity of the chuck of ice

$a=g=9.8 m/s^2$ is the acceleration of gravity (we choose downward as positive direction)

s = 343 m is the vertical displacement (the height of the tower)

Solving for v, we find the final velocity of the object:

$v=\sqrt{u^2+2as}=\sqrt{0+2(9.8)(343)}=82.0 m/s$

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