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creativ13 [48]
3 years ago
14

Porque al tomar agua y la dejo en mi boca no se baja? Curiosidad xd

Physics
1 answer:
Varvara68 [4.7K]3 years ago
7 0

Answer: eso no sabe. Xp

Explanation:

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(PLEASE HELP FAST 20 POINTS)
Lera25 [3.4K]

Everything we see or do in everyday life that involves electricity in any way is the result of electrons moving from one place to another, or from one object to another. <em> (last choice)</em>

4 0
3 years ago
the gravitational force exerted on a baseball is 2.21 N down, a pitcher throws the ball horizontally with velocity 18.0 m/s by u
Ilia_Sergeevich [38]
To have a weight of 2.21N., the ball's mass is (2.21/9.8) = .226kg. 
<span>a) d = 1/2 (vt), = 1/2 (18 x .17), = 1.53m. </span>
<span>b) Acceleration of the ball = (v/t), = 18/.17, = 105.88m/sec^2. </span>
<span>f = (ma), = .226 x 105.88, = 23.92N. </span>
8 0
3 years ago
Read 2 more answers
What is the work done when a 400.n force is use to lift a 400.n object 3.5 meters strait up
alexandr1967 [171]

Answer:

i think it's 1400

Explanation:

w = Force x displacement

w = 400 x 3.5

3 0
3 years ago
The mass of block B is twice the mass of block A, while the mass of the pulley is equal to the mass of block A. The blocks are l
marshall27 [118]

Answer:

C)the right cord pulls on the pulley with greater force than the left cord

Explanation:

As we can see the figure that B is connected to the right string while A is connected to the left string

Now force equation for B as it will move downwards is given as

(2m)g - T_B = (2m)a

similarly for block A which will move upwards we can write the equation as

T_A - mg = ma

now we know that pulley is also rotating so the tangential acceleration of the rope at the contact point with pulley must be same as that of acceleration of the blocks

so here pulley will rotate clockwise direction

So tension in the right string must be more than the left string

So correct answer will be

C)the right cord pulls on the pulley with greater force than the left cord

3 0
3 years ago
Suppose the magnitude of the proton charge differs from the magnitude of the electron charge by a mere 1 part in 109
Oksana_A [137]

Answer:

 A) F = 1.09 10 5 N, b) Yes  

Explanation:

Part A

For this exercise we need the number of free electrons in copper, as the valence of copper +1 there is a free electron for each atom. Let's use the concept of density to find the mass of copper in the sphere

               ρ = m / V

               .m = ρ V = ρ 4/3 π r³

The radius is half the diameter

               r = 1.9 10⁻² / 2 = 0.95 10⁻² m

               ρ = 8960 kg / m3

               m = 8960 4/3 π (0.95 10⁻²)³

               m = 3.2179 10⁻² kg

The molecular weight of copper is 63,546 g / mol which has 6,022 10²³ atoms

With this we can use a rule of proportions to enter the number of atom is this mass

             #_atom = 6.022 10²³ 3.2179 10⁻² / 63.546 10⁻³

             #_atom = 3,049 10²³

Therefore there is the same number of electrons, as they indicate that the charge of the protone and the electon differs by 1/10⁹ the total charge for each spherical is

               q = e / 10⁹    #_atom

               q = e / 10⁹    3,049 1023

               q = 3,049 10⁴  (-1.6 10⁻¹⁹)

               q = -4,878 10-5 C

Electric force is

             F = k q₁q₂ / r²

             F = k q² / r²

             

Let's calculate

             F = 8.99 10⁹ (4.878 10⁻⁵)²2 / (1.4 10⁻²)²

              F = 1.09 10 5 N

This is a force of repulsion.

Part B

 The magnitude of this force is  in very easy to detect

4 0
3 years ago
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