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Novay_Z [31]
2 years ago
7

The universe was 5 percent its current size when light left objects observed now at redshift of ______________

Physics
1 answer:
Nuetrik [128]2 years ago
4 0

The redshift of distant galaxy are larger than those of closer galaxies, which indicates that the galaxy is receding at a faster rate.

  • The Universe was 5 percent its current size when light left objects now at redshift of <u>19</u>.

Reasons:

The size of the universe represented as a scale factor with relation to the redshift can be presented as follows;

\displaystyle \frac{a}{a_0}  =\mathbf{ \frac{1}{1 + z}}

Where;

a₀ = The current size of the Universe

a = The size of the early Universe = 5% of a

Therefore;

\displaystyle \frac{a}{a_0}  =5\% = 0.05=  \frac{1}{1 + z}

\displaystyle 0.05  = \frac{1}{1 + z}

0.05 + 0.05·z = 1

\displaystyle z = \mathbf{ \frac{1 - 0.05}{0.05} } = 19

  • The redshift is of the observed light is, z = <u>19</u>

Learn more here:

brainly.com/question/14459434

brainly.com/question/3654558

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Represent the motion in the number line.

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3 years ago
A rod of very small diameter with a mass 2m and length 3L is placed along the xaxis with one end at the origin. An identical rod
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Answer:

coordinates of the center of mass for these two rods

(x_{cm}, y_{cm})= (\frac{3L}{4},  \frac{3L}{4})cm

Explanation:

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attached is the diagram and solution to the question

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3 years ago
lasie4. A 4 kg object is displaced to the right by a distance of 12 m underthe influence of the following forces: a 17 Nforce pu
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The work done by a constant force in a rectilinear motion is given by:

W=Fd\cos\theta

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\begin{gathered} W=(17)(12)\cos0+(36)(12)\cos30 \\ W=578.123 \end{gathered}

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6 0
1 year ago
An interference pattern is produced by light with a wavelength 550 nm from a distant source incident on two identical parallel s
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Answer:

a

 \theta  =  0.0022 rad

b

 I  =  0.000304 I_o

Explanation:

From the question we are told that  

   The  wavelength of the light is \lambda  = 550 \ nm  =  550 *10^{-9} \ m

    The  distance of the slit separation is  d = 0.500 \ mm = 5.0 *10^{-4} \ m

 

Generally the condition for two slit interference  is  

     dsin \theta =  m \lambda

Where m is the order which is given from the question as  m = 2

=>    \theta  =  sin ^{-1} [\frac{m \lambda}{d} ]

 substituting values  

      \theta  =  0.0022 rad

Now on the second question  

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So the intensity is  

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   I  =  0.000304 I_o

3 0
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s2008m [1.1K]

Answer:

40 j, 80j.

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For 8m, P.E=1*10*8=80 joules.

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