Answer:
I think it is
Step-by-step explanation:
(18.0, 22.0). We are 95% confident that the mean age of university students is between 18 and 22.
Answer:
B) 2 + 4x = 5 - 3 - 3x
Step-by-step explanation:
By simplifying JUST the right side and re-arranging them
2 + 4x = 5 - 3(x + 1),
2 + 4x = 5 - 3x -3,
2 + 4x = 5 -3 - 3x
1 - 2 - 3 - 4 - 5 - 6 - 7 - 8 - 9 - 10 are your team numbers
1 - 2
1 - 3
1 - 4
1 - 5
1 - 6
1 - 7
1 - 8
1 - 9
1 - 10
2 - 3
2 - 4
2 - 5
2 - 6
2 - 7
2 - 8
2 - 9
2 - 10
3 - 4
3 - 5
3 - 6
3 - 7
3 - 8
3 - 9
3 - 10
4 - 5
4 - 6
4 - 7
4 - 8
4 - 9
4 - 10
5 - 6
5 - 7
5 - 8
5 - 9
5 - 10
6 - 7
6 - 8
6 - 9
6 - 10
7 - 8
7 - 9
7 - 10
8 - 9
8 - 10
9 - 10
45 matches in all >.< :)
So find the difference between 1995 and 2022 to make it easier
2022-1995=27
so the rephrased question is
when hazel was x years old, she was 25 years older than son gary who was y old at that time (equation is x is 25 more than y or x=25+y)
in 27 years, (this means x+27 and y+27) hazel's age will be 150% of gary's age (x+27= 150% of y+27)
percent means parts out of 100 so 150%=150/100=15/10=1.5
'of' in math means multiply so
the equations are
x=25+y
x+27=1.5(y+27)
subsitute 25+y for x in second euation
25+y+27=1.5(y+27)
add like terms
y+52=1.5(y+27)
I personally dislike decimals to multiply both sides by 2 to make 2 0.5's or 1 (you are technically supposed to distribute or divide both sides by 1.5) so
2y+104=3(y+27)
distribute
2y+104=3y+81
subtract 2y from both sides
104=y+81
subtract 81 from both sides
23=y
subsitute
x=25+y
x=25+23
x=48
Hazel was 48 and Gary was 23 in the year of 1995
You may have have forgotten to find the measure of A. Which would by using your 6 that you got would be 19.
16X-6=90
96=16X
X=6
8X6-29
48-29
19