Omg u can’t even figure out this? Why are you still going school
We are asked to find the area of the rectangle that has side lengths of 3/4 yard and 5/6 yard.
We know that area of rectangle is width times length.
To find the area of the given rectangle we will multiply both side lengths as:
Therefore, the area of the given rectangle would be square yards.
Answer:
He lost 147.35 marks
Step-by-step explanation:
Take the total marks and subtract the marks he got to find the marks he lost
600-452.65= 147.35
(0,-3) (-4,-27) (1,3) are the correct points
(4,61) <u>doesn't</u> work
X + 0.5y = 3
x^2 - y = 15
from the first equation:-
0.5y = 3 - x
y = 6 - 2x
Substitute for y in second equation:-
x^2 - (6 - 2x) = 15
x^2 + 2x - 21 = 0
x = [-2 +/- sqrt((4 - 4*-21)] / 2
= 3.6904 , -5.6904
Plugging in these into first equation we get
3.6904 + 0.5y = 3 so y = 2(3-3.6904) = -1.3808
-5.6904 + 0.5y = 3 so y = 2(3 + 5.6904) = 17.3808
Solution is x = 3.690, y = -1.381 ; x = -5.690, y = 17.38 ( to 4 s.f's)