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3 years ago

How do I solve this

Mathematics

2 answers:

Kitty [74]3 years ago

8 0

Hello,

$x^2-2x-27=-5x+1\\

x^2-2x+5x-27-1=0\\

x^2+3x-28=0\\

x^2+7x-4x-28=0\\

x(x+7)-4(x+7)=0\\

(x+7)(x-4)=0\\

x=-7\ or\ x=4\\
$

iris [78.8K]3 years ago

3 0

The answer is X1=-7, x2=4.

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H(-4), h(0), h(4), h(8)

DIA [1.3K]

9514 1404 393

Answer:

see attached

Step-by-step explanation:

The first two x-values, -4 and 0, fall in the first part of the function definition.

There is no function definition for x = 4, as the second part only applies for x > 4.

The last x-value, 8, falls in the second part of the function definition.

The function is evaluated by putting the x-value where x is in the expression and doing the arithmetic. For example, ...

h(-4) = -(-4+1)^2 +7 = -(-3)^2 +7 = -9 +7 = -2

h(0) = 6

h(4) = undefined

h(8) = -8/3

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3 years ago

Determine whether The given segments have the same length. Justify your answer

Semenov [28]

We know the distance formula is

$\sqrt{ (x_{2}-x_{1})^2+ (y_{2}-y_{1})^2 }$

Here A( -4,2) and B(1,4)

So length of AB

= $\sqrt{(1-(-4))^2+(4-2)^2} =\sqrt{5^2+2^2} =\sqrt{29}$

Also C(2,1)

Length of BC

= $\sqrt{(2-1)^2+(-1-4)^2} =\sqrt{1^2+(-5)^2} =\sqrt{26}$

So we can see that length of AB is not equal to length of BC

11.

Now AB = $\sqrt{29}$

Also C(2,-1) & D(4,4)

Length of CD

= $\sqrt{(4-2)^2+(4-(-1)) ^2} =\sqrt{2^2+5^2} =\sqrt{29}$

Yes AB = CD

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3 years ago

Drag and drop the correct number to complete the equation. 434÷234=Response area Drag and drop the correct number to complete th

jeka94

Answer:

The answer would be 9(3+4)

Step-by-step explanation:

9(3+4)

= 9(3) + 9(4)

= 27 + 36

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Answer:

The first one.

Step-by-step explanation:

Both of the equations in the parenthesis have the same value, and 1/2 isn't as much as a whole.

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Answer:

Step-by-step explanation:

12/2=6

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