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choli [55]
3 years ago
9

How do I solve this

Mathematics
2 answers:
Kitty [74]3 years ago
8 0
Hello,

x^2-2x-27=-5x+1\\

x^2-2x+5x-27-1=0\\

x^2+3x-28=0\\

x^2+7x-4x-28=0\\

x(x+7)-4(x+7)=0\\

(x+7)(x-4)=0\\

x=-7\ or\ x=4\\

iris [78.8K]3 years ago
3 0
The answer is X1=-7, x2=4.
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Factor 28 + 56t + 28w to identify the equivalent expressions. Choose 2 answers
ra1l [238]

Answer:

28+56t+28w=14(2+4t+2w)\\\\28+56t+28w=28(1+2t+w)

Step-by-step explanation:

28+56t+28w=14\times 2+14\times 4t+14\times 2w\\\\14\ is\ common\ in\ every\ term\\\\28+56t+28w=14(2+4t+2w).........................................(1)\\\\Now\ take\ 2+4t+2w\\\\2+4t+2w=2+2\times 2t+2w\\\\2\ is\ common\\\\2+4t+2w=2(1+2t+1)\\\\Now\ substitute\ this\ in\ equation\ 1\\\\28+56t+28w=14\times 2(1+2t+w)\\\\28+56t+28w==28(1+2t+w)

3 0
3 years ago
Read 2 more answers
When adding two negative integers, how do you determine whether the answer will be positive or negative?
Alenkinab [10]
If it's already a negative number it's going to stay as a negative number
3 0
2 years ago
I will give 30 points if u help now
Amiraneli [1.4K]

Answer:

3. x=16

4. x=51

Step-by-step explanation:

3. 3x-8=x+24

2x=32

x=16

4. 2/3(x+27)= 180-(3x-25)

2/3x+18=180-3x+25

11/3x=187

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5 0
3 years ago
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Assume a warehouse operates 24 hours a day. Truck arrivals follow Poisson distribution with a mean rate of 36 per day and servic
kirill [66]

The expected waiting time in system for typical truck is 2 hours.

Step-by-step explanation:

Data Given are as follows.

Truck arrival rate is given by,   α  = 36 / day

Truck operation departure rate is given,   β= 48 / day

A constructed queuing model is such that so that queue lengths and waiting time can be predicted.

In queuing theory, we have to achieve economic balance between number of customers arriving into system and that of leaving the system whether referring to people or things, in correlating such variables as how customers arrive, how service meets their requirements, average service time and extent of variations, and idle time.

This problem is solved by using concept of Single Channel Arrival with exponential service infinite populate model.

Waiting time in system is given by,

w_{s} = \frac{1}{\alpha - \beta  }

        where w_s is waiting time in system

                   \alpha is arrival rate described Poission distribution

                   \beta is service rate described by Exponential distribution

w_{s} = \frac{1}{\alpha - \beta  }

w_{s} = \frac{1}{48 - 36 }

w_{s} = \frac{1}{12 } day

w_{s} = \frac{1}{12 }  \times 24  hour        ...it is due to 1 day = 24 hours

w_{s} = 2 hours

Therefore, time required for waiting in system is 2 hours.

           

                   

5 0
3 years ago
Hi, I need some help with the last question of the first problem and the answer to the second page.
bulgar [2K]

Answer:

46.9 for the first one

Step-by-step explanation:

So sorry if i'm wrong <3

6 0
2 years ago
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