3 years ago

How do I solve this

2 answers:

8 0

Hello,

$x^2-2x-27=-5x+1\\

x^2-2x+5x-27-1=0\\

x^2+3x-28=0\\

x^2+7x-4x-28=0\\

x(x+7)-4(x+7)=0\\

(x+7)(x-4)=0\\

x=-7\ or\ x=4\\
$

iris [78.8K]3 years ago

3 0

The answer is X1=-7, x2=4.

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