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3 years ago

Find all solutions to the given equation: (2x − 2)(3x +1)(x − 1) = 0

Mathematics

1 answer:

Grace [21]3 years ago

8 0

Answer:

So the solution of the equation will be $x=1,\frac{-1}{3}$

Step-by-step explanation:

We have given polynomial $(2x-2)(3x+1)(x-1)=0$

We have to find all the solution of the equation

For finding the solution we have to equate the factor of the polynomial equal to zero

So $2x-2=0$

x =1

$3x+1=0$

$x=\frac{-1}{3}$

$x-1=0$

x= 1

So the solution of the equation will be $x=1,\frac{-1}{3}$

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I really need help would please like help thanks

ASHA 777 [7]

Hey there!

A reciprocal might be an unfamiliar vocab word, but the concept is really quite simple.

It's just a flipped fraction! Multiplying the flipped fraction by it's reciprocal gets you one, and that's how you check your answer.

So we have:

Reciprocal of 9/10 is 10/9, because 9/10 times 10/9 = 90/90 = 1

Reciprocal of 1/11 is 11/1, because 1/11 times 11/1 = 11/11 = 1

Reciprocal of 10(remember, it's 10/1) is 1/10, because 10/1 times 1/10 = 10/10 = 1

Hope this helps!

4 0

2 years ago

A town is planning a playground. It wants to fence in a rectangular space using an existing wall. What is the greatest area it c

777dan777 [17]

Answer:

1250 $ft^{2}$

Step-by-step explanation:

We are given that the playground is fenced on three sides of the playground and the four side has an existing wall.

Let the length of the rectangle be 'X' feet and width be 'Y' feet.

As the fencing is done using 100 feet of fence. We get the relation between the sides and the fence as, X + 2Y = 100.

As, X + 2Y = 100 → X = 100 - 2Y

Now, the area of the rectangle = XY = X × ( 100 - 2Y ).

i.e Area of the rectangle = $-2Y^{2} +100Y$ .

The general form of a quadratic equation is $y=ax^{2}+bx+c$ .

The maximum value of a quadratic equation is given by $x=\frac{-b}{2a}$ .

Therefore, the greatest value of $-2Y^{2} +100Y$ is at Y = $\frac{-100}{2 \times -2}$ = $\frac{-100}{-4}$ = 25.

Thus, Y = 25 and X = 100 - 2Y → X = 100 - 2 × 25 → X = 50.

Hence, the area of the rectangle is XY = 50 × 25 = 1250 $ft^{2}$ .

3 0

3 years ago

6. Fill in the smallest digit to make the number divisible by:

Degger [83]

Answer:

(i) 71640, 321970

(ii) 1143, 47205, 2316

(iii) 1428, 9252, 7212

(iv) 24620, 9100, 6700

(v) 12320, 59016, 46424

Step-by-step explanation:

(i) In order for any number to be divisible by 5, its last digit must be either 0 or 5.

In this case, we should add a last digit, so we opt for 0 without any doubt since it gives a smaller number than 5 as the last digit: 71640 is smaller than 71645, the same way as 321970 is smaller than our second option, 321975.

(ii) If the sum of a number's digits gives a number divisible by 3, then the main number is also divisible by 3.

This means that we have to do some addition:

1_43: 1 + 4 + 3 = 8. Eight is not divisible by 3. But 9 is. So the smallest digit we can add for it to be divisible by three is 1: 1143.

47_05: 4 + 7 + 0 + 5 = 16. Since 16 is not, the next number that is divisible by 3 is 18, and therefore, the smallest digit we need here is 2: 47205.

_316: 3 + 1 + 6 = 10. Twelve is the next number divisible by 3, and that means 2 is the digit we choose: 2316.

(iii) Only numbers that are divisible by both 2 and 3 are also divisible by 6.

_428: In order for a number to be divisible by 2, its last digit must be 0 or divisible by 2. That is already the case here.

4 + 2 + 8 = 14 which is not divisible by 3. But 15 is. So the smallest digit we need is 1: 1428.

9_52: The number will be divisible by 2. And 9 + 5 + 2 = 16 which is not divisible by 3 but 18 is. This means the smallest digit we need is 2: 9252.

721_: Since the last digit can be any of these 0, 2, 4, 6, 8 for the number to be divisible by two, we will first see what digit we need for it to be divisible by 3.

7 + 2 + 1 = 10 which is not divisible by 3 but 12 is. We will then choose to add 2: 7212.

(iv) A number is divisible by 4 only if the number that is formed by its two last digits is also divisible by 4..

2462_: Since we need to add a last digit, this should be easy. The smallest two-digit-number that starts with 2 and is divisible by four is 20: 24620.

91__: Here we need to add both of the two last digits, and this should be the easiest example! All numbers that end in 00, meaning they have a round number of hundreds, are divisible by 4! Therefore our option is: 9100.

670_: In this case, we apply the same rule from the last example - and we choose 0: 6700.

(v) In order for a number to be divisible by 8, its last three digits need to be divisible by 8, or it can end in 000, since every number having a round number of thousands is also divisible by 8.

1232_: 320 is divisible by 8 since 8 × 40 gives 320. Therefore, our smallest digit here is 0: 12320.

59_16: If we add a 0 here, the last three digits form the number 016, which is divisible by 8. Our choice is again zero: 59016.

4642_: Unfortunately, 420 is not divisible by 8. The next number closest to 420 and which is divisible by 8 is 424. Its division by 8 gives 53. Therefore we should add 4: 46424.

7 0

2 years ago

Find the lengths of sides e, f, & g

valentinak56 [21]

Answer:

e 7 f 5 g is the square root of 74 I don't have a calculator on me sry

8 0

3 years ago

Which of these values are farthest from zero 0.75 2/3 and 0.25

leva [86]

.75 is farthest because 2/3 is .66 (infinitely) and .25 is smaller than both

8 0

3 years ago