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Novosadov [1.4K]
4 years ago
6

How many faces does the solid made from the net below have?​

Mathematics
1 answer:
nikdorinn [45]4 years ago
5 0

Answer:We need to see the net.

Step-by-step explanation:

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Write the grammatical sentence as an algebraic one: Nine less than half a number is twenty-four. ​
soldi70 [24.7K]
Answer:

x/2-9=24

Explanation:

Nine less:
-9
Half a number:
x/2
So nine less than half a number:
x/2-9
Is 24:
=24

So x/2-9=24

To solve for the number:
Add 9 to both sides:
x/2-9+9=24+9
x/2=33
Multiply both sides by 2:
2(x/2)=33(2)
x=66
8 0
3 years ago
You plan on supplementing your income. You would like to withdraw a monthly salary of $1,205.78 from an account paying 5.5% inte
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<span>d.<span>$63,126.00 I think haha</span></span>
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3 years ago
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Round 222,977 to the nearest hundred
erastovalidia [21]
The place the value of 9 is in is the hundreds place.  So, any number greater than 5 is rounded up.  7 is greater than 5, so the 9 becomes a 0 and the next number is increased by 1.  All the values after are marked as a 0.  The answer is 223,000.
4 0
3 years ago
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Simplify tan9x-tan5x / 1+tan9xtan5x<br> (SHOW WORK)
Charra [1.4K]

Answer:

The simplest form is tan(4x)

Step-by-step explanation:

* Lets revise the identity of the compound angles

- tan(a+b)=\frac{tan(a)+tan(b)}{1-tan(a)tan(b)}

- tan(a-b)=\frac{tan(a)-tan(b)}{1+tan(a)tan(b)}

* Lets solve the problem

- Let 9x = 5x + 4x

∴ tan(9x) = tan(5x + 4x)

- Use the rule of the compound angle

∵ \frac{tan(9x)-tan(5x)}{1+tan(9x)tan(5x)} ⇒ (1)

∵ tan(5x+4x)=\frac{tan(5x)+tan(4x)}{1-tan(5x)tan(4x)} ⇒ (2)

∵ tan(9x) = equation (2)

- Substitute (2) in (1)

∴ \frac{\frac{tan(5x)+tan(4x)}{1-tan(5x)tan(4x)}-tan(5x)}{1+(\frac{tan(5x)+tan(4x)}{1-tan(5x)tan(4x)})tan(5x)}

- Multiply up and down by (1 - tan(5x)tan(4x))

∴ \frac{tan(5x)+tan(4x)-tan(5x)[1-tan(5x)tan(4x)]}{1-tan(5x)tan(4x)+tan(5x)[tan(5x)+tan(4x)]}

- Simplify up and down

∴ \frac{tan(5x)+tan(4x)-tan(5x)+tan^{2}(5x)tan(4x)}{1-tan(5x)tan(4x)+tan^{2}(5x)+tan(5x)tan(4x) }

∴ \frac{tan(4x)+tan^{2}(5x)tan(4x)}{[1+tan^{2}(5x)]}

- Take tan(4x) as a common factor up

∴ \frac{tan(4x)[1+tan^{2}(5x)]}{[1+tan^{2}(5x)]}

- Cancel [1 + tan²(5x)] up and down

∴ The answer is tan(4x)

4 0
4 years ago
Answer the question: 4x – 7 = 4x – 7
Pepsi [2]
X could equal anything because of these two equivalent problems on each side. This would be unsolvable, so JOT DOWN the words “no solution”.
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3 years ago
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