1x68
2x34
4x17
Hope that helps
Answer: The required length of the segment AA' is 11 units.
Step-by-step explanation: Given that the point A(5, 11) is reflected across the X-axis.
We are to find the length of the segment AA'.
We know that
if a point (x, y) is reflected across X-axis, then its co-ordinates becomes (x, -y).
So, after reflection, the co-ordinates of the point A(5, 11) becomes A'(5, -11).
Now, we have the following distance formula :
The DISTANCE between two points P(a, b) and Q(c, d) gives the length of the segment PQ as follows :

Therefore, the length of the segment AA' is given by

Thus, the required length of the segment AA' is 11 units.
X=32
Explanation: X/9-1=4
X/8=4
8x4=32
Answer:
90428160.3 ft³
Step-by-step explanation:
The question is on volume of a pyramid with a square base
The formulae for volume of a pyramid is V=( l×w×h)/3
where l is length of pyramid base, w is width of pyramid base and h is the height of the pyramid
The pyramid has a square base thus l=w= 751 feet
The height of the pyramid is h=481 feet
v= (751×751×481)/3
v=90428160.3 ft³