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givi [52]
3 years ago
15

Is 4 a solution for 2X + 9 = 13? Why or Why not?​

Mathematics
2 answers:
MrRa [10]3 years ago
5 0

Answer:

No.

Step-by-step explanation:

2(4) = 8

8 + 9 doesn't equal 13..

Bumek [7]3 years ago
3 0

Answer:

No.

Step-by-step explanation:

2x + 9 = 13

2x + 9 = 13

      -9   -9

2x = 4

2x / 2 = 4 / 2

x = 2

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Please help solve for x..
aalyn [17]

Answer:

x = 1 or x = -1

Step-by-step explanation:

Given equation:

x^{100}-4^x \cdot x^{98}-x^2+4^x=0

Factor out -1:

\implies -1(-x^{100}+4^x \cdot x^{98}+x^2-4^x)=0

Divide both sides by -1:

\implies -x^{100}+4^x \cdot x^{98}+x^2-4^x=0

Rearrange the terms:

\implies 4^x \cdot x^{98}-4^x-x^{100}+x^2=0

\textsf{Apply exponent rule} \quad a^{b+c}=a^b \cdot a^c \quad \textsf{to }x^{100}:

\implies 4^x \cdot x^{98}-4^x-x^{98}x^2+x^2=0

Factor the first two terms and the last two terms separately:

\implies 4^x(x^{98}-1)-x^2(x^{98}-1)=0

Factor out the common term (x^{98}-1) :

\implies (4^x-x^2)(x^{98}-1)=0

<u>Zero Product Property</u>:  If a ⋅ b = 0 then either a = 0 or b = 0 (or both).

Using the <u>Zero Product Property</u>, set each factor equal to zero and solve for x (if possible):

\begin{aligned}x^{98}-1 & = 0 & \quad \textsf{or} \quad \quad4^x-x^2 & = 0 \\x^{98} & =1 & 4^x & = x^2 \\x & = 1, -1 & \textsf{no}& \textsf{ solutions for } x \in \mathbb{R}\end{aligned}

Therefore, the solutions to the given equation are: x = 1 or x = -1

Learn more here:

brainly.com/question/27751281

brainly.com/question/21186424

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2 years ago
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Check picture below, solve for "x" and "y"

unless you've already covered the 30-60-90 triangle, then check your book on them, to see the ratios, using the 30-60-90 ratios is simpler

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