Answer:
Answer: 12
Step-by-step explanation:
Answer:
False
Step-by-step explanation:

Answer: <em>The answer is </em><u><em>9-pack of toaster pastries for $7.56</em></u>
Step-by-step explanation:
<em>Basicly it would be more expensive if you bought 9 for the first option but less for the other.</em>
If y what? I think you're missing part of the question...
Answer:
D
Step-by-step explanation:
Recall that the area of a triangle is given by:

In this case, the base is <em>x</em> and the height is <em>y</em>. Hence:

We can write the following ratios:

Solve for <em>x</em> and <em>y</em>:

Substitute:

And simplify. Hence:

In conclusion, our answer is D.