<u>Answer:</u>
The value of x is in the solution set of 3(x – 4) ≥ 5x + 2 is -10
<u>Solution:</u>
Need to determine which value of x from given option is solution set of 3(x – 4) ≥ 5x + 2
Lets first solve 3(x – 4) ≥ 5x + 2
3(x – 4) ≥ 5x + 2
=> 3x – 12 ≥ 5x + 2
=> 3x – 5x ≥ 12 + 2
=> -2x ≥ 14
=> -x ≥ 7
=> x ≤ -7
All the values of x which are less than or equal to -7 is solution set of 3(x – 4) ≥ 5x + 2. From given option there is only one value that is -10 which is less than -7
Hence from given option -10 is solution set of 3(x – 4) ≥ 5x + 2.
Step-by-step explanation:
5×10³) × (9×10^7)
= 45 × 10^10
= 4.5 × 10¹¹
Answer:
ok i dont know this one
Step-by-step explanation:
Answer:
Inside the jar there's 16 nickels and 35 quarters.
Step-by-step explanation:
Since there are only nickels and quarters in the jar, the sum of the number of nickels and the number of quarters inside it must be equal to the total number of coins in the jar. So
nickels + quarters = 51
We know the total value inside the jar, to obtain this value we must multiply the amount of each kind of coin by it's value and sum it. So we have:
0.05*nickels + 0.25*quarters = 9.55
We now have two equations and two variables, so we can solve them as follows:
nickels + quarters = 51
0.05*nickels + 0.25*quarters = 9.55
From the first equation:
nickels = 51 - quarters
0.05*(51 - quarters) + 0.25*quarters = 9.55
2.55 - 0.05*quarters + 0.25*quarters = 9.55
0.2*quarters = 9.55 - 2.55
quarters = 7/0.2 = 35
nickels = 51 - 35 = 16
Inside the jar there's 16 nickels and 35 quarters.
The correct answer is x>0. This is because the circle is on 0, is hollow, and has an arrow that points right.
