The diagonals are congruent.
hope this helped.
![\bf \qquad \textit{Simple Interest Earned Amount}\\\\ A=P(1+rt)\qquad \begin{cases} A=\textit{accumulated amount}\to &1192\\ P=\textit{original amount deposited}\to& \$800\\ r=rate\to r\%\to \frac{r}{100}\\ t=years\to &14 \end{cases} \\\\\\ 1192=800(1+r14)\implies \cfrac{1192}{800}=1+14r\implies \cfrac{149}{100}=1+14r \\\\\\ \cfrac{149}{100}-1=14r\implies \cfrac{\frac{149}{100}-1}{14}=r](https://tex.z-dn.net/?f=%5Cbf%20%5Cqquad%20%5Ctextit%7BSimple%20Interest%20Earned%20Amount%7D%5C%5C%5C%5C%0AA%3DP%281%2Brt%29%5Cqquad%20%0A%5Cbegin%7Bcases%7D%0AA%3D%5Ctextit%7Baccumulated%20amount%7D%5Cto%20%261192%5C%5C%0AP%3D%5Ctextit%7Boriginal%20amount%20deposited%7D%5Cto%26%20%5C%24800%5C%5C%0Ar%3Drate%5Cto%20r%5C%25%5Cto%20%5Cfrac%7Br%7D%7B100%7D%5C%5C%0At%3Dyears%5Cto%20%2614%0A%5Cend%7Bcases%7D%0A%5C%5C%5C%5C%5C%5C%0A1192%3D800%281%2Br14%29%5Cimplies%20%5Ccfrac%7B1192%7D%7B800%7D%3D1%2B14r%5Cimplies%20%5Ccfrac%7B149%7D%7B100%7D%3D1%2B14r%0A%5C%5C%5C%5C%5C%5C%0A%5Ccfrac%7B149%7D%7B100%7D-1%3D14r%5Cimplies%20%5Ccfrac%7B%5Cfrac%7B149%7D%7B100%7D-1%7D%7B14%7D%3Dr)
you'd get a decimal value for the rate, just multiply it times 100, to get the percentage format of it.
Answer:
![\Huge \boxed{-42}](https://tex.z-dn.net/?f=%5CHuge%20%5Cboxed%7B-42%7D)
Step-by-step explanation:
To solve this problem, first you have to multiply numbers from left to right.
![\displaystyle (7)(-6)](https://tex.z-dn.net/?f=%5Cdisplaystyle%20%287%29%28-6%29)
Make sure to remove parenthesis.
![\displaystyle -7\times6=-42](https://tex.z-dn.net/?f=%5Cdisplaystyle%20-7%5Ctimes6%3D-42)
Therefore, the correct answer is -42.
<h2>I hope this helps!</h2><h2>Have a wonderful blessing day! :) </h2><h2>Good luck!</h2>
Answer: B
Step-by-step explanation:
4(x+3)+2x=6(x+2)
4x+12+2x=6x+12
6x+12=6x+12
12=12
All real solutions
5+2(3+2x)=x+3(x+1)
5+6+4x=x+3x+3
11+4x=4x+3
11=3
No solution