A box has four coins coin 1 has both sides tails coin 2 has both sides heads coin 3 has both sides heads coin 4 if a regular coi n (1 side heads and 1 side tails) if we randomly select one coin from the box and flip, what is the probability we get heads?
1 answer:
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Answer:
6×-27=-3×
+3×
9/9×=27/9
×=3
Answer:
Option A.
Step-by-step explanation:
we know that
The combined area of the 3 windowpanes and frame is equal to
using a graphing tool to solve the quadratic equation
The solution is
see the attached figure
(4x+y)+5
Yes he is correct because the 3 was in the tenths place. so say that the 3 is in the ones place multiply it by 10 and equales 3000. so you are just taking one zero with it
-4(4x+3) + (7x -2) = (-16x + -12) + (7x + 2) = -16 + -12 + 7x + 2 = -9x -10
