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Vladimir79 [104]
3 years ago
8

HELP PLEASE

Mathematics
1 answer:
olga55 [171]3 years ago
6 0
The slope of a line includes a x and y axis, or y/x. Your two answers are -7/4 and -8/5. Hope that helps!
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If AC = x + 5 and AB = 3x - 1... what is the length of BC?
Hatshy [7]
If B is the midpoint of AC, then |AB| = |AC|.
|AB| = 3x + 2
|BC| = 5x - 10
Therefore we have the equation:
3x + 2 = 5x - 10     |subtract 2 from both sides
3x = 5x - 12      |subtract 5x from both sides
-2x = -12      |divide both sides by (-2)
x = 6

Read more on Brainly.com - brainly.com/question/11324096#readmore
4 0
3 years ago
Determine the answer to 3 + (-5) and explain the steps using a number line
Andreas93 [3]

Answer:

-2

Step-by-step explanation:

3 - 5 = -2

Place the dot on -2 on the number line that is on your problem as the answer. To show the steps on the number line, use your jumps to go back. For example, your starting point will be on 3, and then use your jumps to go back by 5; that means you go into the negatives. For this case, it is -2.

4 0
3 years ago
The number of days, d, to build a house is given by
Alenkasestr [34]

Answer:

Step-by-step explanation: 7 more workers

6 0
2 years ago
(4,?), is on the line below. Find the other half of the coordinate. Y= - 3/4x + 3
riadik2000 [5.3K]
If you plug in the x-coordinate into your equation for the line, you get 
y = -3(4)/4 + 3
y = -3 + 3
y = 0
4 0
3 years ago
Write the standard equation of a circle having endpoints of a diameter at (-1, 6) and (9,-8).
MAXImum [283]

Answer:

r ^{2} = (x-4)^2 + (y+1)^{2}

Given:

endpoints at (-1, 6) and (9, -8)

Solve for:

the standard equation of a circle having endpoints of a diameter at (-1, 6) and (9,-8).

Step-by-step explanation:

d=\sqrt{(x_{2} -x_{1})^2+(y_{2} -y_{1})^2}

d=\sqrt{(9-(-1))^2+(-8-6)^2}

d=\sqrt{10^2+-14^2}

d=\sqrt{100+196}

d=\sqrt{296}

d=2\sqrt{74}

r=\frac{d}{2}

r=\frac{2\sqrt{74} }{2}

r=\sqrt{74}

Center = (\frac{x_{1}+x_{2} }{2} ,\frac{y_{1}+y_{2} }{2})

= (\frac{-1+9}{2}, \frac{6+(-8)}{2} )

=(4, -1)

Center = (4,-1) \\and\\r = \sqrt{74}

Equation:

(\sqrt{74}) ^{2} = (x-4)^2 + (y+1)^{2}

r ^{2} = (x-4)^2 + (y+1)^{2}

*This took forever so I hoped it helped lol*

5 0
2 years ago
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